已知向量a=(根号3sinx,cosx),b=(cosx,cosx),函数f(x)=2a·b-1当x∈[π/6,π/2]时,若f(x)=1,求x.
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![已知向量a=(根号3sinx,cosx),b=(cosx,cosx),函数f(x)=2a·b-1当x∈[π/6,π/2]时,若f(x)=1,求x.](/uploads/image/z/1043879-23-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8Fa%3D%28%E6%A0%B9%E5%8F%B73sinx%2Ccosx%29%2Cb%3D%28cosx%2Ccosx%29%2C%E5%87%BD%E6%95%B0f%28x%29%3D2a%C2%B7b-1%E5%BD%93x%E2%88%88%5B%CF%80%2F6%2C%CF%80%2F2%5D%E6%97%B6%2C%E8%8B%A5f%EF%BC%88x%EF%BC%89%3D1%2C%E6%B1%82x.)
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