有两道数学题以前记的笔记有点看不懂了,关于函数,求函数的值域(用判别式法)f(x)=x²-x/x²-x+1令y=x²-x/x²-x+1yx²-yx+y=x²-x(y-1)x²+(1-y)x+y=0当y-1=0 即y=1,1=0 ∴y≠1当y-1≠1时 即
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![有两道数学题以前记的笔记有点看不懂了,关于函数,求函数的值域(用判别式法)f(x)=x²-x/x²-x+1令y=x²-x/x²-x+1yx²-yx+y=x²-x(y-1)x²+(1-y)x+y=0当y-1=0 即y=1,1=0 ∴y≠1当y-1≠1时 即](/uploads/image/z/10512854-62-4.jpg?t=%E6%9C%89%E4%B8%A4%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%E4%BB%A5%E5%89%8D%E8%AE%B0%E7%9A%84%E7%AC%94%E8%AE%B0%E6%9C%89%E7%82%B9%E7%9C%8B%E4%B8%8D%E6%87%82%E4%BA%86%2C%E5%85%B3%E4%BA%8E%E5%87%BD%E6%95%B0%2C%E6%B1%82%E5%87%BD%E6%95%B0%E7%9A%84%E5%80%BC%E5%9F%9F%EF%BC%88%E7%94%A8%E5%88%A4%E5%88%AB%E5%BC%8F%E6%B3%95%EF%BC%89f%28x%29%3Dx%26%23178%3B-x%2Fx%26%23178%3B-x%2B1%E4%BB%A4y%3Dx%26%23178%3B-x%2Fx%26%23178%3B-x%2B1yx%26%23178%3B-yx%2By%3Dx%26%23178%3B-x%28y-1%29x%26%23178%3B%2B%281-y%29x%2By%3D0%E5%BD%93y-1%3D0+%E5%8D%B3y%3D1%2C1%3D0+%E2%88%B4y%E2%89%A01%E5%BD%93y-1%E2%89%A01%E6%97%B6+%E5%8D%B3)
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