[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.A.in honour of him B.in his honourC.in whose honour D.in which honour翻译包括选项,并分析
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![[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.A.in honour of him B.in his honourC.in whose honour D.in which honour翻译包括选项,并分析](/uploads/image/z/10639245-21-5.jpg?t=%5BD68%5D+The+famous+scientist%2C_____+a+dinner+party+will+be+held+tonight%2Cit+to+arrive+soon.A.in+honour+of+him+B.in+his+honourC.in+whose+honour+D.in+which+honour%E7%BF%BB%E8%AF%91%E5%8C%85%E6%8B%AC%E9%80%89%E9%A1%B9%2C%E5%B9%B6%E5%88%86%E6%9E%90)
[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.A.in honour of him B.in his honourC.in whose honour D.in which honour翻译包括选项,并分析
[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.
A.in honour of him B.in his honour
C.in whose honour D.in which honour
翻译包括选项,并分析
[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.A.in honour of him B.in his honourC.in whose honour D.in which honour翻译包括选项,并分析
翻译:这位著名的科学家,将很快到场(出席)那个为其庆祝而于今晚举行的宴会.
此题考查定语从句关系词用法.
1.主句是:The famous scientist is to arrive soon.
而括号中间是一个非限制性定语从句,修饰句子主语the famous scientist.
2.将其代入该定语从句中,变化为:
a dinner party will be held tonight (in the famous scientist's honour)
= (in the famous scientist's honour) a dinner party will be held tonight
= (in whose honour) a dinner party will be held tonight
其中,关系代词whose等同于先行词的所有格形式,在定语从句中充当定语.
3.另:此句也可以如此变化:
a dinner party will be held tonight (in honour of the famous scientist)
= (in honour of whom) a dinner party will be held tonight
其中,whom代替先行词the famous scientist,在定语从句中充当of的宾语.
4.上述两种变化各含有一个固定短语:
in one's honour = in honour of sb,意思是“为庆祝/为纪念/为表达对...的敬意”.
5.AB等于是一个单独的简单句,并不是定语从句,因为它们没有关系词引导;
D中的which只能代指事物sth,不能代指人sb,排除.