5x-1/3y=2 ,5x+2/3y=1
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/29 11:55:38
![5x-1/3y=2 ,5x+2/3y=1](/uploads/image/z/1064036-20-6.jpg?t=5x-1%2F3y%3D2+%2C5x%2B2%2F3y%3D1)
x)3575R161
mKGOP*UaҺ@iJ[];=m]~O=OMgP([#|-m_\gu
d!}hցp+^I6
[Su. e\
5x-1/3y=2 ,5x+2/3y=1
5x-1/3y=2 ,5x+2/3y=1
5x-1/3y=2 ,5x+2/3y=1
5x-1/3y=2 ,.(1)
5x+2/3y=1 .(2)
(2)-(1) y=-1
带入(1)得:5x+1/3=2
x=1/3
5x-1/3y=2 ,(1)
5x+2/3y=1 (2)
(2)-(1)
y=-1
代入(1)
5x+1/3=2
5x=5/3
x=1/3
y=-1
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
(2x+y-1)(2x-y+1)-(3x+y)(3x-y),其中x=5分之1,
x+y=1 5x-2y=8 3x-y=7 2x-y=3x表示y和用y表示x
(x+2y)(x-2y)-(2x-y)的平方+(3x-y)(2x-5y)其中x=-1 y=13分之1
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
3X+5y=2 x+y=1
3x-2y=1 4x-5y
化简求值(x+2y)^2-(2x+y)(2x-y)-5y(y-x) 其中 x=1/3 y= -1/2
{x+y}/2+{x-y}/3=5 {x+y}/2-{x+y}/3=-1 解二元一次方程 3Q!| {x+y}/2+{x-y}/3=5 | {x+y}/2-{x+y}/3=-1
x-y/7 - x+y/10 =1/2 2(x-y)-5(x+y)=3修改、、、、(x-y)/7-(x+y)/10=1/2 2(x-y)-5(x+y)=3
(x-y)/4+(x+y)/5=1/4 (x+y)/9-(x-y)/3=//2(x-y)/4+(x+y)/5=1/4(x+y)/9-(x-y)/3=//2
7x-3y/5=5x-y/3-x+y/2 x-1/5=y+1/3
x-{y-2x+[3x-3(y+2x)+5y]},其中=2分之1,y=-1
x-{y-2x+[3x-3(y+2x)+5y]},其中=2分之1,y=-1
解方程组{(x-2)(y+3)=(x+1)(y-1) {(x+1)(y+1)=(x-1)(y+5)