求:[1+4/(x-1)]∧(x+1),即1+4/(x-1)的x+1次方,当X趋于∞时的极限,我自己的解法如下:(采换元法) 令1/y=4/x-1,y=4x+1,代入原式得(1+1/y)∧(4y+2)到这里再怎么转换式子才能利用公式lim(1+1/x)∧x(X趋于
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![求:[1+4/(x-1)]∧(x+1),即1+4/(x-1)的x+1次方,当X趋于∞时的极限,我自己的解法如下:(采换元法) 令1/y=4/x-1,y=4x+1,代入原式得(1+1/y)∧(4y+2)到这里再怎么转换式子才能利用公式lim(1+1/x)∧x(X趋于](/uploads/image/z/107229-21-9.jpg?t=%E6%B1%82%EF%BC%9A%5B1%2B4%2F%EF%BC%88x-1%29%5D%E2%88%A7%28x%2B1%29%2C%E5%8D%B31%2B4%2F%EF%BC%88x-1%29%E7%9A%84x%2B1%E6%AC%A1%E6%96%B9%2C%E5%BD%93X%E8%B6%8B%E4%BA%8E%E2%88%9E%E6%97%B6%E7%9A%84%E6%9E%81%E9%99%90%2C%E6%88%91%E8%87%AA%E5%B7%B1%E7%9A%84%E8%A7%A3%E6%B3%95%E5%A6%82%E4%B8%8B%EF%BC%9A%EF%BC%88%E9%87%87%E6%8D%A2%E5%85%83%E6%B3%95%EF%BC%89+%E4%BB%A41%2Fy%3D4%2Fx-1%2Cy%3D4x%2B1%2C%E4%BB%A3%E5%85%A5%E5%8E%9F%E5%BC%8F%E5%BE%97%EF%BC%881%2B1%2Fy%29%E2%88%A7%284y%2B2%29%E5%88%B0%E8%BF%99%E9%87%8C%E5%86%8D%E6%80%8E%E4%B9%88%E8%BD%AC%E6%8D%A2%E5%BC%8F%E5%AD%90%E6%89%8D%E8%83%BD%E5%88%A9%E7%94%A8%E5%85%AC%E5%BC%8Flim%281%2B1%2Fx%29%E2%88%A7x%28X%E8%B6%8B%E4%BA%8E)
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