化简:sin^2αcos^2β-cos^2αsin^2β+cos^2α-cos^2β具体步骤,
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化简:sin^2αcos^2β-cos^2αsin^2β+cos^2α-cos^2β具体步骤,
化简:sin^2αcos^2β-cos^2αsin^2β+cos^2α-cos^2β具体步骤,
化简:sin^2αcos^2β-cos^2αsin^2β+cos^2α-cos^2β具体步骤,
sin^2αcos^2β-cos^2αsin^2β+cos^2α-cos^2β
=sin^2αcos^2β-cos^2β-cos^2αsin^2β+cos^2α
=(sin^2α-1)cos^2β-cos^2α(sin^2β-1)
=-(1-sin^2α)cos^2β+cos^2α(1-sin^2β)
=-cos^2αcos^2β+cos^2αcos^2β
=0
sin²acos²b-cos²asin²b+cos²a-cos²b
=(sin²a-1)cos²b-cos²a(1-sin²b)
=-cos²acos²b-cos²acos²b
=-2cos²acos²b
化简sin(α+β)-2cosαsinβ/2cosαcosβ-cos(α+β)
化简:sin^2αcos^2β-cos^2αsin^2β+cos^2α-cos^2β具体步骤,
sin(α+β)-2cosαsinβ/2cosαcosβ-cos(α+β)
化简(sinα+cosβ)^2
化简sin²αsin²β+cos²αcos²β-1/2cos2αcosβ
化简sin²αsin²β+cos²αcos²β-1/2cos2αcosβ
sin(α+β)-2sinαcosβ/2sinαsinβ+cos(α+β)化简
化简:sin(α+β)-2sinαcosβ/2sinαsinβ+cos(α+β)
化简sin(α+β)-2sinαcosβ 除以 2sinαsinβ+cos(α+β)
化简 sin(α+β)-2sinαcosβ/1sinαsinβ+cos(α+β)
求证cosα^2+cos(α+β)^2-2cosαcosβcos(α+β)=sinβ^2
化简sin^2α+sin^2β-sin^2αsin^2β+cos^2cos^2β
化简sin^2α+sin^2β-sin^2cos^2β-cos^2αsin^2β
cos方α+cos方(α+β)-2cosαcosβcos(α+β)-sin方β
sin(α+β)-2sinαcosβ/2sinαsinβ+cos(α+β)
若sinαsinβ+cosαcosβ=0,则sinαcosα+sinβcosβ= .1若sinαsinβ+cosαcosβ=0,则sinαcosα+sinβcosβ= 2已知sin(α+β)=1,则cos(α+2β)+sin(2α+β)=急,
化简sin^2α+sin^2β+2sinαsinβcos(α+β)
化简:(sin²αtanα+cos²α/tanα+2sinαcosα)sinαcosα