(8x+4)X5=(11x+1)X7+1解方程,拜托各位,快点!

(8x+4)X5=(11x+1)X7+1解方程,拜托各位,快点! ( )x5=( )x7=5分之4x(( )x5=( )x7=5分之4x( )=98分之11x( )=1 x1-x2+x3=1x2-x3+x4=21若x1,x2,x3,x4,x5满足方程组 x3-x4+x5=3x4-x5+x1=4x5-x1+x2=5求x2 x3 x4的值2已知 x1+x4+x6+x7=39 x2+x4+x5+x7=49 x3+x5+x6+x7=41 x4+x7=13 x5+x7=14 x6+x7=9 x1+x2+x3+x4+x5+x6+x7=9求x7的值若x1,x2,x3,x4,x5满足方程组 x1-x x8+x7+x6 +x5+x4+x3+x2+x+1因式分解 x8+x7+x6+x5+x4+x3+x2+x+1因式分解 sn=1/1x3+4/3x5+9/5x7+```````+n2/(2n-1)x(2n+1) 2X/1x3+2X/3x5+2X/5x7+…+2X/2003x2005=2004 (1-1/2x4)x(1-3/3x5)x(1-5/4x6)x(1-7/5x7)x(1-9/6x8)x(1-11/7x9)x(1-13/8x10)x(1-15/9x11) 15(18+X)x7/30=18x5+3X 因式分解:X15+X14+X13+X12+X11+X10+X9+X8+X7+X6+X5+X4+X3+X2+X+1= ( x^14 )( x + 1 ) + ( x^12 )( x + 1 ) +……+ x( x + 1 ) + ( x + 1 )= ( x + 1 )[ ( x^14 + x^12 ) + ( x^10 + x^8 ) + ( x^6 + x^4 ) + x + 1 ]= ( x + 1 )[ ( x^12 )( x + 1 ) + ( x^8 )( 一道数学题:如果1+x+x2+x3=0,求x+x2+x3+x4+x5+x6+x7+x8的值 7(x-9-5-7)+0x9+1x5+2x7=y6(x-5-2-1)+15x1+14x2+13x5=y 2X/1x3+2X/3x5+2X/5x7+2x/7x9+2x/9x11=10 x=? 1+2X3+4X5+6X7+8X9=505请回复 1+2X3+4X5+6X7+8X9=1005运用( ) [ ] 添加（）[ ] {} 1+2X3+4X5+6X7+8X9=1005 填括号使等式成立1+2x3+4x5+6x7+8x9=4455 1+2X3+4X5+6X7+8X9=303