1、如图,在正方形ABCD中,E为CD边上一点,F为BC延长线上一点,CE=CF,∠BEC=60°,则∠EFD等于多少度?答案是15°第一题图字母是 A DEB C F
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![1、如图,在正方形ABCD中,E为CD边上一点,F为BC延长线上一点,CE=CF,∠BEC=60°,则∠EFD等于多少度?答案是15°第一题图字母是 A DEB C F](/uploads/image/z/10914313-49-3.jpg?t=1%E3%80%81%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2CE%E4%B8%BACD%E8%BE%B9%E4%B8%8A%E4%B8%80%E7%82%B9%2CF%E4%B8%BABC%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%E4%B8%80%E7%82%B9%2CCE%3DCF%2C%E2%88%A0BEC%3D60%C2%B0%2C%E5%88%99%E2%88%A0EFD%E7%AD%89%E4%BA%8E%E5%A4%9A%E5%B0%91%E5%BA%A6%3F%E7%AD%94%E6%A1%88%E6%98%AF15%C2%B0%E7%AC%AC%E4%B8%80%E9%A2%98%E5%9B%BE%E5%AD%97%E6%AF%8D%E6%98%AF+A+DEB+C+F)
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