(x+y+z)(x-y+z)+(y-x+z)(y-x-z)求过程

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/03 20:36:45
(x+y+z)(x-y+z)+(y-x+z)(y-x-z)求过程
xN@_w2iyB@W[ؘImژHhߥ20x/ cQsɝ;䑥̣ ^C!485d&+3Ȼ/byFxCEHXE %Nayd  e{rL=:Q[˥+U]b>;3~}D;AK3!~+h/4x1)I6n, ص%FBkbuB!++.l[ޖv1hvPw`%h&i?{3']YD

(x+y+z)(x-y+z)+(y-x+z)(y-x-z)求过程
(x+y+z)(x-y+z)+(y-x+z)(y-x-z)求过程

(x+y+z)(x-y+z)+(y-x+z)(y-x-z)求过程
(x+y+z)(x-y+z)+(y-x+z)(y-x-z)
=(x+y+z)(x-y+z)-(y-x+z)(x-y+z)
=((x+y+z)-(y-x+z))(x-y+z)
=(2x)(x-y+z)
=2x(x-y+z)
如需请追问
如无请采纳!

先看题,分解成两部分,以 + 号为界,可见只要把 + 号左边第二个公因式提出“- ”号,就可以合并了。
(x+y+z)(x-y+z)+(y-x+z)(y-x-z)
= -(x+y+z)(y-x-z)+(y-x+z)(y-x-z)
=(y-x-z)(y-x+z-x-y-z)
=2x(x+z-y)

(x+y+z)(x-y+z)+(y-x+z)(y-x-z)
=(x+y+z)(x-y+z)-(y-x+z)(x+z-y)
=(x-y+z)[(x+y+z)-(y-x+z)]
=(x-y+z)(x+y+z-y+x-z)
=(x-y+z)2x
=2x(x-y+z)