作业帮已知:A=x^2-3xy+y^2,B=x^2-5xy+2y^2,求3A-[(-4A+2B)-(2A-B)]的值,其中xy满足(x+y)^2+|x+3|=0
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![已知:A=x^2-3xy+y^2,B=x^2-5xy+2y^2,求3A-[(-4A+2B)-(2A-B)]的值,其中xy满足(x+y)^2+|x+3|=0](/uploads/image/z/1092317-5-7.jpg?t=%E5%B7%B2%E7%9F%A5%3AA%3Dx%5E2-3xy%2By%5E2%2CB%3Dx%5E2-5xy%2B2y%5E2%2C%E6%B1%823A-%5B%28-4A%2B2B%29-%282A-B%29%5D%E7%9A%84%E5%80%BC%2C%E5%85%B6%E4%B8%ADxy%E6%BB%A1%E8%B6%B3%28x%2By%29%5E2%2B%7Cx%2B3%7C%3D0)
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已知:A=x^2-3xy+y^2,B=x^2-5xy+2y^2,求3A-[(-4A+2B)-(2A-B)]的值,其中xy满足(x+y)^2+|x+3|=0
已知:A=x^2-3xy+y^2,B=x^2-5xy+2y^2,求3A-[(-4A+2B)-(2A-B)]的值,其中xy满足(x+y)^2+|x+3|=0
已知:A=x^2-3xy+y^2,B=x^2-5xy+2y^2,求3A-[(-4A+2B)-(2A-B)]的值,其中xy满足(x+y)^2+|x+3|=0
原式=3A-[(-4A+2B)-(2A-B)]=3A-[-4A+2B-2A+B]=3A-[-6A+3B]=3A+6A-3B=9A-3B.∵A=x²-3xy+y²,B=x²-5xy+2y².∴代入原式可得,原式=9(x²-3xy+y²)-3(x²-5xy+2y²)=6x²-12xy+3y².∵(x+y)²+|x+3|=0.∴必有x=-3,y=3.代入原式=6×(-3)²-12×(-3)×3+3×3²=3=9(6+12+3)=9×21=189.∴原式=189.
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