已知三角形ABC的三个内角,满足A+B=2B,设x=cos(A-C)/2,f(x)=cosB(1/cosA+1/cosC)已知三角形ABC的三个内角,满足A+C=2B,设x=cos(A-C)/2,f(x)=cosB(1/cosA+1/cosC),求:(1)试求函数f(x)的解析式及其定义域(2)判断其单
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![已知三角形ABC的三个内角,满足A+B=2B,设x=cos(A-C)/2,f(x)=cosB(1/cosA+1/cosC)已知三角形ABC的三个内角,满足A+C=2B,设x=cos(A-C)/2,f(x)=cosB(1/cosA+1/cosC),求:(1)试求函数f(x)的解析式及其定义域(2)判断其单](/uploads/image/z/1095903-63-3.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E4%B8%89%E4%B8%AA%E5%86%85%E8%A7%92%2C%E6%BB%A1%E8%B6%B3A%2BB%3D2B%2C%E8%AE%BEx%3Dcos%28A-C%29%2F2%2Cf%28x%29%3DcosB%281%2FcosA%2B1%2FcosC%29%E5%B7%B2%E7%9F%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E4%B8%89%E4%B8%AA%E5%86%85%E8%A7%92%2C%E6%BB%A1%E8%B6%B3A%2BC%3D2B%2C%E8%AE%BEx%3Dcos%28A-C%29%2F2%2Cf%28x%29%3DcosB%281%2FcosA%2B1%2FcosC%29%2C%E6%B1%82%EF%BC%9A%EF%BC%881%EF%BC%89%E8%AF%95%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E5%8F%8A%E5%85%B6%E5%AE%9A%E4%B9%89%E5%9F%9F%EF%BC%882%EF%BC%89%E5%88%A4%E6%96%AD%E5%85%B6%E5%8D%95)
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