求解一元三次方程2x∧3 - 3x∧2 + 1 = 0

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求解一元三次方程2x∧3 - 3x∧2 + 1 = 0
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求解一元三次方程2x∧3 - 3x∧2 + 1 = 0
求解一元三次方程
2x∧3 - 3x∧2 + 1 = 0

求解一元三次方程2x∧3 - 3x∧2 + 1 = 0
2x^3 - 3x^2 + x - x + 1 = 0
x*(2x^2 - 3x + 1) - (x -1) = 0
x*(x-1)*(2x-1) - (x -1) = 0
(x-1)*[x*(2x - 1) - 1] = 0
(x-1)*[2x^2 - x - 1] = 0
(x-1)*[(x -1)*(2x+1)] = 0
(x-1)^2 * (2x + 1) = 0
所以,这个方程只有两个
x = 1 或 x = -1/2

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