在反应CI2+2NaOH=NaCI+NaCIO+H2O的变化中,当产生23.4gNaCI时,转移电子总数为( )A.1.204*10^23个B.6.02*10^23个C.4.816*10^23个D.2.408*10^23个
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![在反应CI2+2NaOH=NaCI+NaCIO+H2O的变化中,当产生23.4gNaCI时,转移电子总数为( )A.1.204*10^23个B.6.02*10^23个C.4.816*10^23个D.2.408*10^23个](/uploads/image/z/11159739-27-9.jpg?t=%E5%9C%A8%E5%8F%8D%E5%BA%94CI2%2B2NaOH%3DNaCI%2BNaCIO%2BH2O%E7%9A%84%E5%8F%98%E5%8C%96%E4%B8%AD%2C%E5%BD%93%E4%BA%A7%E7%94%9F23.4gNaCI%E6%97%B6%2C%E8%BD%AC%E7%A7%BB%E7%94%B5%E5%AD%90%E6%80%BB%E6%95%B0%E4%B8%BA%EF%BC%88+%EF%BC%89A.1.204%2A10%5E23%E4%B8%AAB.6.02%2A10%5E23%E4%B8%AAC.4.816%2A10%5E23%E4%B8%AAD.2.408%2A10%5E23%E4%B8%AA)
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