y=[e^(1/x^2)arctan(x^2+x+1)]/[(x-1)(x+2)] 的渐近线有几条⊙﹏⊙b汗是y=[e^(1/x^2)]*arctan[(x^2+x+1)/[(x-1)(x+2)]] 的渐近线有几条

来源：学生作业帮助网编辑：作业帮时间：2024/08/30 14:17:07

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y=[e^(1/x^2)arctan(x^2+x+1)]/[(x-1)(x+2)] 的渐近线有几条⊙﹏⊙b汗是y=[e^(1/x^2)]*arctan[(x^2+x+1)/[(x-1)(x+2)]] 的渐近线有几条
y=[e^(1/x^2)arctan(x^2+x+1)]/[(x-1)(x+2)] 的渐近线有几条
⊙﹏⊙b汗是
y=[e^(1/x^2)]*arctan[(x^2+x+1)/[(x-1)(x+2)]] 的渐近线有几条

y=[e^(1/x^2)arctan(x^2+x+1)]/[(x-1)(x+2)] 的渐近线有几条⊙﹏⊙b汗是y=[e^(1/x^2)]*arctan[(x^2+x+1)/[(x-1)(x+2)]] 的渐近线有几条
x->0时,y->-无穷
有一条渐近线 x=0
x->无穷时,
lim y=(1*π/2)/无穷=0
x->负无穷时
lim y=(-π/2)/(-无穷)=0
所以有渐近线 y=0
y'=(-2/x³)e^(1/x²)arctan(x²+x+1)(x-1)^(-1)(x+2)^(-1)
+e^(1/x²)[(2x+1)/((x²+x+1)²+1)](x-1)^(-1)(x+2)^(-1)
-e^(1/x²)arctan(x²+x+1)(x-1)^(-2)(x+2)^(-1)
-e^(1/x²)arctan(x²+x+1)(x-1)^(-1)(x+2)^(-2)
lim x->无穷 y'
=0+0-0-0
=0
lim x->-无穷 y'
=0
所以没有斜向的渐近线
渐近线x轴y轴

求y=e^(arctan(x^1/2))的导数 y=arctan（x^2+1）求y=e^arctan(1/x)的导数 x^2+y^2=e^(arctan（y/x）),求dy/dx令F(x,y)=x^2+y^2-e^arctan(y/x)=0对x求偏导 Fx = 2x-e^arctan(y/x) * 1/[1+(y/x)^2] * [-y/(x^2)]=2x + y/(x^2+y^2) * e^arctan(y/x)然后e^arctan(y/x)用题目中的x^2+y^2代替就可以把即Fx=2x+y对y求偏导 arctan(y)=x+1, y=? 求导y=arctan[2x/(1-x^2)] 急等求导 Y=ARCTAN x/1+x^2 y=arctan(e^x)求y的导数曲线y=e^(x^(-2))arctan((x+1)/(x-1))的水平和垂直渐近线分别是? y=arctan(1/x)求导 y=arctan（x/2）求导? 求导 y=(arctan x)^2 求y=arctan(e^x)的导数 y=arctan(e^x)求函数的导数 y=2x*arctan(y/x),求y‘’ z=arctan x/(1+y^2),则dz=? y=arctan（2x+1）导数求导数:y=arctan(根号x^2+1)

y=[e^(1/x^2)arctan(x^2+x+1)]/[(x-1)(x+2)] 的渐近线有几条⊙﹏⊙b汗 是y=[e^(1/x^2)]*arctan[(x^2+x+1)/[(x-1)(x+2)]] 的渐近线有几条

y=[e^(1/x^2)arctan(x^2+x+1)]/[(x-1)(x+2)] 的渐近线有几条⊙﹏⊙b汗是y=[e^(1/x^2)]*arctan[(x^2+x+1)/[(x-1)(x+2)]] 的渐近线有几条