化简[sin(2A+B)]/sinA-2cos(A+B)
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化简[sin(2A+B)]/sinA-2cos(A+B)
化简[sin(2A+B)]/sinA-2cos(A+B)
化简[sin(2A+B)]/sinA-2cos(A+B)
[sin(2A+B)]/sinA-2cos(A+B)
=[sin(A+B+A)]/sinA-2cos(A+B)
=[sin(A+B)cosA+cos(A+B)sinA]/sinA-2cos(A+B)
=[sin(A+B)cosA-cos(A+B)sinA]/sinA
=sin(A+B-A)/sinA
=sinB/sinA