证明(sina+cosa-1)(sina-cosa+1)除以sin2a等于tana\2
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证明(sina+cosa-1)(sina-cosa+1)除以sin2a等于tana\2
证明(sina+cosa-1)(sina-cosa+1)除以sin2a等于tana\2
证明(sina+cosa-1)(sina-cosa+1)除以sin2a等于tana\2
(sina+cosa-1)(sina-cosa+1)/sin2a
=[sina^2-(cosa-1)^2]/sin2a
=[sina^2-cosa^2+2cosa-1]/sin2a
=[-2cosa^2+2cosa]/sin2a
=[-2cosa^2+2cosa]/(2sina*cosa)
=[-cosa+1]/sina
=tan(a/2)
证明=[(sina+cosa)+(sina+cosa)²]/(1+sina+cosa) =(sina+cosa)(1+sina+cosa)/(1+sina+cosa)
证明:cosa/(1+sina)-sina/(1+cosa)=2(cosa-sina)/(1+sina+cosa)
证明:|sina|+|cosa|≥1
证明 cosa/(1+sina0-sina/(1+cosa)=2(cosa-sina)/(1+sina+cos)cosa/(1+sina)-sina/(1+cosa)=2(cosa-sina)/(1+sina+cos)
证明sin2a/(1+sina+cosa)=sina+cosa-1
证明:(tana-sina)(cota-cosa)=(1-sina)(1-cosa)
证明sin2a/(1+sina+cosa)=sina+cosa-1
证明:sin2a/(1+sina+cosa)=sina+cosa-1
证明(1+sin2a)/(cosa+sina)=cosa+sina
证明:2(cosa-cosa)/(1+cosa+cosa)=cosa/(1+sina)-sina/(1+cosa).
证明:(1+sina+cosa)/(1-sina+cosa)=cosa/(1-sina)
证明(cosa-sina+1)/(cosa+sina+1)=(1-sina)/cosa
利用三角函数证明 【COSa-SINa+1】/【COSa+SINa+1】等于 【1-SINa】/【COSa】
证明(1-cos^2a)/(sina-cosa)-(sina+cosa)/(tan^2-1)=sina+cosa
证明(1+sina+cosa+2sinacosa)/1+sina+cosa=sina+cosa
证明(1-cos^2a)/(sina+cosa)-(sina+cosa)/(tan^2a-1)=sina+cosa
证明1+sina+cosa+2sinacosa/1+sina+cosa=sina+cosa,
证明:(1+sina-cosa)/(1-sina-cosa)+(1-sina-cosa)/(1+sina-cosa)=-2seca