计算:1-[8/(x^2-4)][(x^2+4)/4x]-1]/(1/2-1/x)
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/26 11:01:35
![计算:1-[8/(x^2-4)][(x^2+4)/4x]-1]/(1/2-1/x)](/uploads/image/z/1121418-18-8.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A1-%5B8%2F%28x%5E2-4%29%5D%5B%28x%5E2%2B4%29%2F4x%5D-1%5D%2F%281%2F2-1%2Fx%29)
x){nuemQgk
bhhTkWh$铬GΆ<CHSBIMZۤW?,oT։M
mT7BAd`,YT yv ll
计算:1-[8/(x^2-4)][(x^2+4)/4x]-1]/(1/2-1/x)
计算:1-[8/(x^2-4)][(x^2+4)/4x]-1]/(1/2-1/x)
计算:1-[8/(x^2-4)][(x^2+4)/4x]-1]/(1/2-1/x)
原式=1-[8/(x+2)(x-2)][(x²+4x+4)/4x]/[(x-2)/2x]
=1-[8/(x+2)(x-2)][(x+2)²/4x][2x/(x-2)]
=1-4(x+2)/(x-2)²
=(x²-4x+4-4x-8)/(x-2)²
=(x²-8x-4)/(x²-4x+4)
计算:[(x+2)/(x+3) - (x+1)/(x+2) + (x+4)/(x+5) - (x+3)/(x+4) / (x^2 + 7x + 13)/(x^2 + 8x + 15)
计算(x+/1x)(x^2+1/x^2)(x^4+1/x^4)(x^8+1/x^8)(x^16+1/x^16)(x^2-1)
计算(x+1)(x+2)(x+3)(x+4)
如何计算 (x+1)(x+2)(x+3)(x+4)
计算(X-1)(X-2)(X-3)(X-4)
(x-1)(x-2)(x-3)(x-4)-24计算
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
计算:[4(x-2)^2+12(x+2)(x-2)-8(x-1)^2(x-2)]乘4(x-2)
1.计算 :[4(x-2)+12(x+2)(x-2)-8(x-2)(x-1)]÷4(x-2)
计算:(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x^32+1)
计算:(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x^32+1)
计算:1-[8/(x^2-4)]/(1/x-1/2)*[1-(x^2+4)/4x]
计算:1 - 8/(x^2-4)/(1/x-1/2)*[1-(x^2+4)/4x]
计算:1-[8/(x^2-4)][(x^2+4)/4x]-1]/(1/2-1/x)
(x-1/2)(x^2+1/2x+1/4)(x^3+1/8)计算
计算:x+2/x^2-2x-x-1/x^2-4x+4
分式计算:(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)
计算:x^-4/(x-2)(x-1)+x^-4/(x+2)(x+1)