X=xx,#include#includeusing namespace std;class point {public:point(int xx=0,int yy=0) {X=xx;Y=yy;}int getX() {return X;}int getY() {return Y;}friend float fdist(point &a,point &b);private:int X,Y;};float fdist(point &p1,point &p2){double x=double(p1.

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X=xx,#include#includeusing namespace std;class point {public:point(int xx=0,int yy=0) {X=xx;Y=yy;}int getX() {return X;}int getY() {return Y;}friend float fdist(point &a,point &b);private:int X,Y;};float fdist(point &p1,point &p2){double x=double(p1.
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X=xx,#include#includeusing namespace std;class point {public:point(int xx=0,int yy=0) {X=xx;Y=yy;}int getX() {return X;}int getY() {return Y;}friend float fdist(point &a,point &b);private:int X,Y;};float fdist(point &p1,point &p2){double x=double(p1.
X=xx,
#include
#include
using namespace std;
class point
{
public:
point(int xx=0,int yy=0) {X=xx;Y=yy;}
int getX() {return X;}
int getY() {return Y;}
friend float fdist(point &a,point &b);
private:
int X,Y;};
float fdist(point &p1,point &p2)
{double x=double(p1.X-p2.X);
double y=double(p1.Y-p2.Y);
return float (sqrt(x*x+y*y));
}
void main(){point myp1(1,1),myp2(4,5);
cout

X=xx,#include#includeusing namespace std;class point {public:point(int xx=0,int yy=0) {X=xx;Y=yy;}int getX() {return X;}int getY() {return Y;}friend float fdist(point &a,point &b);private:int X,Y;};float fdist(point &p1,point &p2){double x=double(p1.
xx,yy是作为一个变量,是个整体的,不能分开,程序中没有x或y,单写一个程序会出错,X=xx,Y=yy是赋值语句,就是把xx的值赋给X,yy的值赋给Y

7/xx+x+1/xx-1=2/xx-x c++代码,#include using namespace std; //声明class Point;Point operator+(Point &a,Point &b);//定义点类class Point { public:int x,y; Point(){}Point(int xx,int yy){x=xx;y=yy;}void print(){ cout c++ 求三角形周长和面积#include#include using namespace std;class Point{public:Point(double xx=0 ,double yy=0 ){x =xx;y=yy;}Point(Point&p);double getX(){return x ;}double getY(){return y;}private:double x,y;};Point::Point(Point&p){x=p.x;y=p.y X=xx,#include#includeusing namespace std;class point {public:point(int xx=0,int yy=0) {X=xx;Y=yy;}int getX() {return X;}int getY() {return Y;}friend float fdist(point &a,point &b);private:int X,Y;};float fdist(point &p1,point &p2){double x=double(p1. 利用公式求cos x的近似值,精确度为10-6 #include#define PI 3.14159main(){int n,xx;float t,sum,x;printf(请输入弧度x=π/xx对应的分母值:);scanf(%d,&xx);x=PI/xx;t=x;n=0;sum=0;do{sum+=t;t=-t*x*x/(n+1)*(n+2);n+=2;}while(fabs(t)>=1e 帮我注释一下,让我看看懂.# include class XX{protected:int k;public:XX ( int n = 5 ) :k (n) { }XX ( ){ cout 实在看不懂#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std;int cases;int main() {double cl = clock();scanf(%d, #include #include main() { int x,y; float m; for(x=0;x 已知x/(xx+x+1)=a,求xx/(xxxx+xx+1)的值 已知：3x=xx-x+1求（xxxx+xx+1）分之xx x/xx+x+1=1/4 求xx/xxxx+xx+1 7/（XX+X)+1/（xx-x) =6/（xx-1） 解分式方程7/（XX+X)+1/（xx-x) =6/（xx-1） 7/（XX+X)+1/（xx-x) =6/（xx-1） x表示1-9的数,x13/xx=xx,1748/xx=xx,x不能重复 请各位大神帮我看看这个指针到底哪里出错了?#include#includeusing namespace std;class point{public:point();point(int xx,int yy){x=xx;y=yy;}point();int getx(){return x;}private:int x,y;};int main(){point *p=new point;point a(2,3);p=&a (x-y)(x+y)(xx-yy)=? XXX*XX=XX*XX=3624,X内填写1-9,数字不能重复