{3x+4y+z=14 x+5y+2z=17 2x+2y-z=3
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/28 05:45:33
![{3x+4y+z=14 x+5y+2z=17 2x+2y-z=3](/uploads/image/z/113258-2-8.jpg?t=%7B3x%2B4y%2Bz%3D14+x%2B5y%2B2z%3D17+2x%2B2y-z%3D3)
x)66Ԯ54Q662**ulm +/!,$5z`$zF`=ç{}M+*jL EFz`gs:MN1T eOv/~ںb4P
沧t~*.H̳y
ab
{3x+4y+z=14 x+5y+2z=17 2x+2y-z=3
{3x+4y+z=14 x+5y+2z=17 2x+2y-z=3
{3x+4y+z=14 x+5y+2z=17 2x+2y-z=3
3x+4y+z=14 .1
x+5y+2z=17 .2
2x+2y-z=3.3
1式+3式得5x+6y=17.4
3式*2+2式得5x+9y=23.5
有4和5得x=1,y=2
代入3
得z=3
即x=1,y=2,z=3
已知2x+5y+4z=15.7x+y+3z=14 则x+y+z=?
三元一次方程组,1.x-2y+z=9 2x+y+3z=10 3x+2y1.x-2y+z=92x+y+3z=103x+2y-z2.3x-5y+2z=14x+5y-z=5X-5y+3z=-23.7x+2y-z=76x-y+z=74x+3y+z=94.4x+3y-2z=-75x-6y+z=12x+z=-25.2x+3y-4z=-23x-2y+5z=262x+5z=31
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x/2=y/3=z/5 x+3y-z/x-3y+z
x+y/2=z+x/3=y+z/4 x+y+z=27
x+2y=3x+2z=4y+z 求x:y:z
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
x+y=5 2x+3y-z=9 x-y+z=4
①3x-4y+z=14x+5y+2z=172x+2y-z=3② x:y=3:2y:z=5:4x+y+z=66
x+y+z=6 x+2y+3z=14 y+1=z
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
已知:4x-5y+2z=0 x+4y-3z=0则:(x*x+y*y+z*z)/(x*y+y*z+z*x)=____.
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
2x+y+3z=14 x-y+z=4 3x-y-z=2
{2x-y+3z=14 x-y+z=4 3x-y-z=2