C++ 利用公式PI/4=1-1/3+1/5-1/7+...计算PI的近似值.#includevoid main(){int s=-1,i,n;double PI=0;printf("enter n:");scanf("%d",&n);for(i=1;i
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![C++ 利用公式PI/4=1-1/3+1/5-1/7+...计算PI的近似值.#includevoid main(){int s=-1,i,n;double PI=0;printf(](/uploads/image/z/1138350-30-0.jpg?t=C%2B%2B+%E5%88%A9%E7%94%A8%E5%85%AC%E5%BC%8FPI%2F4%3D1-1%2F3%2B1%2F5-1%2F7%2B...%E8%AE%A1%E7%AE%97PI%E7%9A%84%E8%BF%91%E4%BC%BC%E5%80%BC.%23includevoid+main%28%29%7Bint+s%3D-1%2Ci%2Cn%3Bdouble+PI%3D0%3Bprintf%28%22enter+n%3A%22%29%3Bscanf%28%22%25d%22%2C%26n%29%3Bfor%28i%3D1%3Bi)
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C++ 利用公式PI/4=1-1/3+1/5-1/7+...计算PI的近似值.#includevoid main(){int s=-1,i,n;double PI=0;printf("enter n:");scanf("%d",&n);for(i=1;i
C++ 利用公式PI/4=1-1/3+1/5-1/7+...计算PI的近似值.
#include
void main()
{int s=-1,i,n;
double PI=0;
printf("enter n:");
scanf("%d",&n);
for(i=1;i
C++ 利用公式PI/4=1-1/3+1/5-1/7+...计算PI的近似值.#includevoid main(){int s=-1,i,n;double PI=0;printf("enter n:");scanf("%d",&n);for(i=1;i
更改以下即可:PI=PI+(double)s/i;
否则s/i是按整型取结果的
亲测可用,
#include
void main()
{
\x09int s=-1,i,n;
\x09double PI=0.0;
\x09printf("enter n:");
\x09scanf("%d",&n);
\x09for(i=1;i