如图,△ABC的角平分线AD,BE相交于点P,(1)在图1中,分别画出点P到边AC,BC,BA的垂线段PF,PG,PH,这3条线段相为什么?(2)在图2中,∠ABC是直角,∠C=60°,其余条件都不变,请你判断并写出PE与PD之间的数量关
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![如图,△ABC的角平分线AD,BE相交于点P,(1)在图1中,分别画出点P到边AC,BC,BA的垂线段PF,PG,PH,这3条线段相为什么?(2)在图2中,∠ABC是直角,∠C=60°,其余条件都不变,请你判断并写出PE与PD之间的数量关](/uploads/image/z/11451489-33-9.jpg?t=%E5%A6%82%E5%9B%BE%2C%E2%96%B3ABC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BFAD%2CBE%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9P%2C%281%29%E5%9C%A8%E5%9B%BE1%E4%B8%AD%2C%E5%88%86%E5%88%AB%E7%94%BB%E5%87%BA%E7%82%B9P%E5%88%B0%E8%BE%B9AC%2CBC%2CBA%E7%9A%84%E5%9E%82%E7%BA%BF%E6%AE%B5PF%2CPG%2CPH%2C%E8%BF%993%E6%9D%A1%E7%BA%BF%E6%AE%B5%E7%9B%B8%E4%B8%BA%E4%BB%80%E4%B9%88%3F%EF%BC%882%EF%BC%89%E5%9C%A8%E5%9B%BE2%E4%B8%AD%2C%E2%88%A0ABC%E6%98%AF%E7%9B%B4%E8%A7%92%2C%E2%88%A0C%3D60%C2%B0%2C%E5%85%B6%E4%BD%99%E6%9D%A1%E4%BB%B6%E9%83%BD%E4%B8%8D%E5%8F%98%2C%E8%AF%B7%E4%BD%A0%E5%88%A4%E6%96%AD%E5%B9%B6%E5%86%99%E5%87%BAPE%E4%B8%8EPD%E4%B9%8B%E9%97%B4%E7%9A%84%E6%95%B0%E9%87%8F%E5%85%B3)
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