已知x2+4x+3/x+1=0,先化简,再求x2/x-3+3-x/9

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已知x2+4x+3/x+1=0,先化简,再求x2/x-3+3-x/9
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已知x2+4x+3/x+1=0,先化简,再求x2/x-3+3-x/9
已知x2+4x+3/x+1=0,先化简,再求x2/x-3+3-x/9

已知x2+4x+3/x+1=0,先化简,再求x2/x-3+3-x/9
已知(x²+4x+3)/(x+1)=0,先化简,再求x²/(x-3)+(3-x)/9;【题目是这样的吗?】
(x²+4x+3)/(x+1)=(x+1)(x+3)/(x+1)=x+3=0,故得x=-3
于是x²/(x-3)+(3-x)/9=9/(-6)+(6/9)=-3/2+2/3=-5/6

(x2+4x+3)/(x+1)=0
(x+1)(x+3)/(x+1)=0
∴x+3=0
x=-3

∴x²/(x-3)+3-x/9
=9/(-3-3)+3-3/9
=-9/6+3-1/3
=7/6

后面的分式分子分母不太清楚
参考http://58.130.5.100//