若n∈N*,则当n=1或n≥5时,n^2<2n;证明所得的结论; 当n=5时,若n∈N*,则当n=1或n≥5时,n^2<2n;证明所得的结论;当n=5时,n2<2n成立 …假设n=k(k≥5)时,k^2<2k …则当n=k+1时,2k+1=2•2k>2•k^2
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![若n∈N*,则当n=1或n≥5时,n^2<2n;证明所得的结论; 当n=5时,若n∈N*,则当n=1或n≥5时,n^2<2n;证明所得的结论;当n=5时,n2<2n成立 …假设n=k(k≥5)时,k^2<2k …则当n=k+1时,2k+1=2•2k>2•k^2](/uploads/image/z/11465995-67-5.jpg?t=%E8%8B%A5n%E2%88%88N%2A%2C%E5%88%99%E5%BD%93n%3D1%E6%88%96n%E2%89%A55%E6%97%B6%2Cn%5E2%EF%BC%9C2n%EF%BC%9B%E8%AF%81%E6%98%8E%E6%89%80%E5%BE%97%E7%9A%84%E7%BB%93%E8%AE%BA%EF%BC%9B+%E5%BD%93n%3D5%E6%97%B6%2C%E8%8B%A5n%E2%88%88N%2A%2C%E5%88%99%E5%BD%93n%3D1%E6%88%96n%E2%89%A55%E6%97%B6%2Cn%5E2%EF%BC%9C2n%EF%BC%9B%E8%AF%81%E6%98%8E%E6%89%80%E5%BE%97%E7%9A%84%E7%BB%93%E8%AE%BA%EF%BC%9B%E5%BD%93n%3D5%E6%97%B6%2Cn2%EF%BC%9C2n%E6%88%90%E7%AB%8B+%E2%80%A6%E5%81%87%E8%AE%BEn%3Dk%EF%BC%88k%E2%89%A55%EF%BC%89%E6%97%B6%2Ck%5E2%EF%BC%9C2k+%E2%80%A6%E5%88%99%E5%BD%93n%3Dk%2B1%E6%97%B6%2C2k%2B1%3D2%26%238226%3B2k%EF%BC%9E2%26%238226%3Bk%5E2)
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