求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值 求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 22:45:38
![求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值 求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值](/uploads/image/z/11471803-43-3.jpg?t=%E6%B1%82f%28x%29%3D2cos%28x%2B%CF%80%2F3%29-1%2C%E6%B1%82%E5%BD%93x%E2%88%88%5B%CF%80%2F6%2C%CF%80%5D%E7%9A%84%E6%9C%80%E5%80%BC+%E6%B1%82f%28x%29%3D2cos%28x%2B%CF%80%2F3%29-1%2C%E6%B1%82%E5%BD%93x%E2%88%88%5B%CF%80%2F6%2C%CF%80%5D%E7%9A%84%E6%9C%80%E5%80%BC)
x){)MB(9XB|P::Bf:bjy6i2$eml'}6uó9k^ZtƧ~ھ"UO'x6g7ceӑt'|U)x6}i S,ګ
27|~'>e4 +笀(1w
/&=m4#y6n
S:p7 AͶ5/.H̳ Q|
求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值 求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值
求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值
求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值
求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值 求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值
从函数本身就可看出函数的最小正周期为2π,当x+π/3=2πk(k属于z)及x=2πk-π/3时取最大值,x+π/3=2πk+π/2及x=2πk+π/6时取最小值 当x∈[π/6,π]时可以知道f(x)在[π/6,2π/3]单调递减,[2π/3,π]单调递增,故最小值为-3,最大值为f(π/6)=-1
f(sinx)=1+cos(2x),求f(x),
若函数f(x)=[2cos^3 x-sin^2 (x+π)-2cos (-x-π)+1]/[2+2cos^2(7π+x)+cos(-x)],(1)求证f(x)是偶函数若函数f(x)=[2cos^3 x-sin^2 (x+π)-2cos (-x-π)+1]/[2+2cos^2(7π+x)+cos(-x)],(1)求证f(x)是偶函数 (2)求f(π/3)的值
设f(x)=e^3x-1×cos(2πx+π/3),求导数
已知函数f(x)=cos(π/3+x)*cos(π/3-x),g(x)=1/2sin2x-1/4,求f(x)的最小正周期
设函数f (x)=cos(2x-π/3)-2sin平方x (1)求函数f(x
已知f(x)=cos^2x/1+sin^2x求f'(π/4)求导
f(sin x)=3-cos 2x,求f(cos x)=?
f(sin x)=3-cos 2x求f(cos x)
f(sin x)=cos 2x +1 求 f(cos x)
f(x)=2(cosx)^3+sin(360°-x)^2-cos(180°-x)-3/2+2cos(180°+x)+cos(-x)求f(π/3)
f'(sin x)=1-cos x 求f''(x)
化简f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1(1)化简f(x);(2)求f(π/12)的值
设f(sin x/2 )-1+cos x ,求f(x)、f(cos x/2 ).
求函数f(x)=cos^2x+sinx-1
已知函数f(x)=sin(2x+π/6)-cos(2x+π/3)+2cos²x(1)求f(π/12)的值(2)求f(x)的最大值及相应x的值
求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值 求f(x)=2cos(x+π/3)-1,求当x∈[π/6,π]的最值
已知f(x)=cos(2x-π/3)+sin²x-cosx(1)求f(x)周期及对称轴方程(2)g(x)=f²(x)+f(x),求g(x)值域
设f(x)=[2cos^3 x-sin^2 (360°-x)+2sin(90°+x)+1]/2+2cos^2 (180°+x)+cos(-x),求f(π/3)的值设f(x)=[2cos^3 x-sin^2 (360°-x)+2sin(90°+x)+1]/2+2cos^2 (180°+x)+cos(-x),求f(π/3)的值