试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?已知abc=1,试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?(对不起,一开始错了,
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![试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?已知abc=1,试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?(对不起,一开始错了,](/uploads/image/z/11484532-28-2.jpg?t=%E8%AF%95%E5%B0%86a%2Fab%2Ba%2B1%2Cb%2Fbc%2Bb%2B1%2Cc%2Fac%2Bc%2B1%E5%8C%96%E6%88%90%E5%90%8C%E5%88%86%E6%AF%8D%E7%9A%84%E5%BC%8F%E5%AD%90%3F%E5%B7%B2%E7%9F%A5abc%3D1%2C%E8%AF%95%E5%B0%86a%2Fab%2Ba%2B1%2Cb%2Fbc%2Bb%2B1%2Cc%2Fac%2Bc%2B1%E5%8C%96%E6%88%90%E5%90%8C%E5%88%86%E6%AF%8D%E7%9A%84%E5%BC%8F%E5%AD%90%EF%BC%9F%28%E5%AF%B9%E4%B8%8D%E8%B5%B7%EF%BC%8C%E4%B8%80%E5%BC%80%E5%A7%8B%E9%94%99%E4%BA%86%EF%BC%8C)
试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?已知abc=1,试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?(对不起,一开始错了,
试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?
已知abc=1,试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?(对不起,一开始错了,
试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?已知abc=1,试将a/ab+a+1,b/bc+b+1,c/ac+c+1化成同分母的式子?(对不起,一开始错了,
因为abc=1,所以有
a/ab+a+1=a/ab+a+abc=1/b+1+bc
c/ac+c+1=c/ac+c+abc=1/a+1+ab=a/a(ab+a+1)=1/(b+1+bc)a
综合2个式子可看出公分母为a(bc+b+1)=abc+ab+a=ab+a+1
所以最后结果为
a/ab+a+1不变
b/bc+b+1=ab/ab+a+1
c/ac+c+1=1/ab+a+1
a/ab+a+1,b/bc+b+1,c/ac+c+1
a/ab+a+1=(ac+cba^2+abc)/abc
b/bc+b+1=(ab+acb^2+abc)/abc
c/ac+c+1=(bc+abc^2+abc)/abc详细点a/ab+a+1=1/b+ab/b+b/b=(1+ab+b)/b b/bc+b+1=1/c+bc/c+c/c=(1+bc+c)/c c/ac+c+...
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a/ab+a+1,b/bc+b+1,c/ac+c+1
a/ab+a+1=(ac+cba^2+abc)/abc
b/bc+b+1=(ab+acb^2+abc)/abc
c/ac+c+1=(bc+abc^2+abc)/abc
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