若实数x.y满足根号x+y-3+(x-2y)^2=0.则根号2xy=

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若实数x.y满足根号x+y-3+(x-2y)^2=0.则根号2xy=
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若实数x.y满足根号x+y-3+(x-2y)^2=0.则根号2xy=
若实数x.y满足根号x+y-3+(x-2y)^2=0.则根号2xy=

若实数x.y满足根号x+y-3+(x-2y)^2=0.则根号2xy=
根号x+y-3+(x-2y)^2=0
必有:
x+y-3=0
x-2y=0
解得:y=1;x=2
2xy=2*2=4

根号x+y-3+(x-2y)^2=0.则
x+y-3=0
x-2y=0
解得:y=1,x=2
根号2xy=根号(2*2*1)=2

因为实数X,y 满足根号x+y-3+(x-2y)^2=0
所以x+y-3=0
x-2y=0
解这个方程组得:x=2 y=1
2xy=2*2*1=4
所以根号2xy=根号4=2

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