如图,在梯形ABCD中,AD∥BC,EA⊥AD,M是AE上一点,F、G分别是AB、CM的中点,且∠BAE=∠MCE,∠MBE=45°,则给出以下五个结论:①AB=CM;②AB⊥CM;③∠BMC=90°;④EF=EG;⑤△EFG是等腰直角三角形.上述结论中始
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![如图,在梯形ABCD中,AD∥BC,EA⊥AD,M是AE上一点,F、G分别是AB、CM的中点,且∠BAE=∠MCE,∠MBE=45°,则给出以下五个结论:①AB=CM;②AB⊥CM;③∠BMC=90°;④EF=EG;⑤△EFG是等腰直角三角形.上述结论中始](/uploads/image/z/11535107-59-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAD%E2%88%A5BC%2CEA%E2%8A%A5AD%2CM%E6%98%AFAE%E4%B8%8A%E4%B8%80%E7%82%B9%2CF%E3%80%81G%E5%88%86%E5%88%AB%E6%98%AFAB%E3%80%81CM%E7%9A%84%E4%B8%AD%E7%82%B9%2C%E4%B8%94%E2%88%A0BAE%3D%E2%88%A0MCE%2C%E2%88%A0MBE%3D45%C2%B0%2C%E5%88%99%E7%BB%99%E5%87%BA%E4%BB%A5%E4%B8%8B%E4%BA%94%E4%B8%AA%E7%BB%93%E8%AE%BA%EF%BC%9A%E2%91%A0AB%3DCM%EF%BC%9B%E2%91%A1AB%E2%8A%A5CM%EF%BC%9B%E2%91%A2%E2%88%A0BMC%3D90%C2%B0%EF%BC%9B%E2%91%A3EF%3DEG%EF%BC%9B%E2%91%A4%E2%96%B3EFG%E6%98%AF%E7%AD%89%E8%85%B0%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2.%E4%B8%8A%E8%BF%B0%E7%BB%93%E8%AE%BA%E4%B8%AD%E5%A7%8B)
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