四道相似三角形题目,1.已知:如图,△BAC∽△EAF,∠FAE=∠CAB,求证:∠ABE=∠ACF2.如图,∠AOD=90°,OA=OB=BC=CD,求证:(1)△BAC∽△BDA;(2)∠ACB+∠ADB=45°3.如图,矩形ABCD中,AB=4cm,点E在边AB的延长线上,BE
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/03 17:04:06
![四道相似三角形题目,1.已知:如图,△BAC∽△EAF,∠FAE=∠CAB,求证:∠ABE=∠ACF2.如图,∠AOD=90°,OA=OB=BC=CD,求证:(1)△BAC∽△BDA;(2)∠ACB+∠ADB=45°3.如图,矩形ABCD中,AB=4cm,点E在边AB的延长线上,BE](/uploads/image/z/11543810-50-0.jpg?t=%E5%9B%9B%E9%81%93%E7%9B%B8%E4%BC%BC%E4%B8%89%E8%A7%92%E5%BD%A2%E9%A2%98%E7%9B%AE%2C1.%E5%B7%B2%E7%9F%A5%EF%BC%9A%E5%A6%82%E5%9B%BE%2C%E2%96%B3BAC%E2%88%BD%E2%96%B3EAF%2C%E2%88%A0FAE%3D%E2%88%A0CAB%2C%E6%B1%82%E8%AF%81%EF%BC%9A%E2%88%A0ABE%3D%E2%88%A0ACF2.%E5%A6%82%E5%9B%BE%2C%E2%88%A0AOD%3D90%C2%B0%2COA%3DOB%3DBC%3DCD%2C%E6%B1%82%E8%AF%81%EF%BC%9A%EF%BC%881%EF%BC%89%E2%96%B3BAC%E2%88%BD%E2%96%B3BDA%EF%BC%9B%EF%BC%882%EF%BC%89%E2%88%A0ACB%2B%E2%88%A0ADB%3D45%C2%B03.%E5%A6%82%E5%9B%BE%2C%E7%9F%A9%E5%BD%A2ABCD%E4%B8%AD%2CAB%3D4cm%2C%E7%82%B9E%E5%9C%A8%E8%BE%B9AB%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%2CBE)
xTmoV+QJz_0N6# @a[V2-'UdMڑ,TI ?a6$h&U>MtϹ<:~@Un_UKV1>ۥuT)啈aF+h{ Ed^l؍u67=nLB&a!&
$Hq/nj{"ǽ2X'EMEI6ZgCT_FF;B^m,ZOHŵչ6Z$Fcow
\R?QC %5:oD