微积分解答帮忙求下这个积分,谢谢.∫[(1-X2)^2/(1+X2)^2]^1/2.Xdx(商的平方根)∫{[(1-X^2)^2/(1+X^2]^1/2}.Xdx(1-X平方除以1+X平方的商的平方根再乘以X,谢谢) 谢谢你的回答,不过感觉不是那样,根号是
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/10 18:47:09
![微积分解答帮忙求下这个积分,谢谢.∫[(1-X2)^2/(1+X2)^2]^1/2.Xdx(商的平方根)∫{[(1-X^2)^2/(1+X^2]^1/2}.Xdx(1-X平方除以1+X平方的商的平方根再乘以X,谢谢) 谢谢你的回答,不过感觉不是那样,根号是](/uploads/image/z/11546260-52-0.jpg?t=%E5%BE%AE%E7%A7%AF%E5%88%86%E8%A7%A3%E7%AD%94%E5%B8%AE%E5%BF%99%E6%B1%82%E4%B8%8B%E8%BF%99%E4%B8%AA%E7%A7%AF%E5%88%86%2C%E8%B0%A2%E8%B0%A2.%E2%88%AB%5B%281-X2%29%5E2%2F%281%2BX2%29%5E2%5D%5E1%2F2.Xdx%28%E5%95%86%E7%9A%84%E5%B9%B3%E6%96%B9%E6%A0%B9%EF%BC%89%E2%88%AB%7B%5B%281-X%5E2%29%5E2%2F%281%2BX%5E2%5D%5E1%2F2%7D.Xdx%281-X%E5%B9%B3%E6%96%B9%E9%99%A4%E4%BB%A51%2BX%E5%B9%B3%E6%96%B9%E7%9A%84%E5%95%86%E7%9A%84%E5%B9%B3%E6%96%B9%E6%A0%B9%E5%86%8D%E4%B9%98%E4%BB%A5X%EF%BC%8C%E8%B0%A2%E8%B0%A2%29+%E8%B0%A2%E8%B0%A2%E4%BD%A0%E7%9A%84%E5%9B%9E%E7%AD%94%EF%BC%8C%E4%B8%8D%E8%BF%87%E6%84%9F%E8%A7%89%E4%B8%8D%E6%98%AF%E9%82%A3%E6%A0%B7%EF%BC%8C%E6%A0%B9%E5%8F%B7%E6%98%AF)
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