设f(x)=√x²+4,g(x)√x²-4,求f(a-1/a)+g(a+1/a)的值(a大于等于1)
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设f(x)=√x²+4,g(x)√x²-4,求f(a-1/a)+g(a+1/a)的值(a大于等于1)
设f(x)=√x²+4,g(x)√x²-4,求f(a-1/a)+g(a+1/a)的值(a大于等于1)
设f(x)=√x²+4,g(x)√x²-4,求f(a-1/a)+g(a+1/a)的值(a大于等于1)
你那个根号应该过了4吧
希望对您有帮助
f(a-1/a)+g(a+1/a)=√[a-(1/a)]²+4+√[a+(1/a)]²-4=√[a+(1/a)]²+√[a-(1/a)]²∵a≥1∴上式=[a+(1/a)]+[a-(1/a)]=2a