2y²+4y=y+2这道题怎么用分解因式法解

怎么算啊这个：X²+4X+Y²-2Y+5=0 则X²+Y²=?²²²²²²²²²²²²X²+4X+Y²-2Y+5X=0 则X²+Y²=? 2y²+4y=y+2这道题怎么用分解因式法解 2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y x²-4y² x+2y---------- ÷ --------分数线x²+2xy+y² x²+xyx²-4y² x+2y----------÷--------分数线x²+2xy+y² x²+xy(x+2y)(x-2y)x(x+y)=----------------(x+y)(x+y)(x+2y)(x-y)x=------(x+y)这样对了吗? 化简再求值[(x²+y²）²-4x²y²]÷(x²-y²）其实,x=2,y=2/3. 4m²（2x-3y)²-m²（3x-2y)²=? 已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y 就是已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y /4y就是除以4y 4y-y的平方=2这是什么方程?怎么解,4y-y²=2 已知,x²+2y²-2xy-4y+4=0,求x²+y²的值 已知x²+4x+y²-2y+5=0,则x²+y²= 1.(x+y)²-4xy=( )²2.x²-（ ）+25y²=（ )²3.x²-8x²y²+16y四次方=（ ）²4.7.2²-2.8²= . 已知x² -XY = 2,Y² -XY= 5,求x² - 4x Y+ Y² = 2x² + xY -3Y² = x² 已知x² -XY = 2,Y² -XY= 5,求x² - 4x Y+ Y² = 2x² + xY -3Y² = x² + xY- 2Y² =求x² - 4x Y+ Y² = 已知2x+3y=0,求代数式1.5x+4y/3x-2y 2.x²+xy-y²/x²-xy+y² 如果2x-y=8,求代数式[(x²+y²)-(x-y)²=2y(x-y)]/(4y)的值 1.已知x/x-1=（y²+4y-1）/（y²+4y-2）,则y²+4y-x的值为多少? 已知2x-y=10 【（x²+y²）-（x-y)²+2y（x-y）】÷4y 过程 「（x²+y²）-（x-y）²+2y（x-y）」÷4y,其中2x-y=18 2x-y=10 【（x²+y²）-（x-y)²+2y（x-y）】÷4y