求解以下两式的值:1、(2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1=?2、如下式:已知:(5x-2)*(2x+a)=10x^2+6x+b,求a,b的值.说明:2^2:2的2次方.第二题刚才自己做出来了哈哈,a=2;b=-4,知不道对
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![求解以下两式的值:1、(2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)+1=?2、如下式:已知:(5x-2)*(2x+a)=10x^2+6x+b,求a,b的值.说明:2^2:2的2次方.第二题刚才自己做出来了哈哈,a=2;b=-4,知不道对](/uploads/image/z/1167367-31-7.jpg?t=%E6%B1%82%E8%A7%A3%E4%BB%A5%E4%B8%8B%E4%B8%A4%E5%BC%8F%E7%9A%84%E5%80%BC%EF%BC%9A1%E3%80%81%EF%BC%882%5E1%2B1%29%282%5E2%2B1%29%282%5E4%2B1%29%282%5E8%2B1%29%282%5E16%2B1%29%282%5E32%2B1%29%282%5E64%2B1%29%2B1%3D%3F2%E3%80%81%E5%A6%82%E4%B8%8B%E5%BC%8F%EF%BC%9A%E5%B7%B2%E7%9F%A5%EF%BC%9A%EF%BC%885x-2%29%2A%282x%2Ba%29%3D10x%5E2%2B6x%2Bb%2C%E6%B1%82a%2Cb%E7%9A%84%E5%80%BC.%E8%AF%B4%E6%98%8E%EF%BC%9A2%5E2%EF%BC%9A2%E7%9A%842%E6%AC%A1%E6%96%B9.%E7%AC%AC%E4%BA%8C%E9%A2%98%E5%88%9A%E6%89%8D%E8%87%AA%E5%B7%B1%E5%81%9A%E5%87%BA%E6%9D%A5%E4%BA%86%E5%93%88%E5%93%88%EF%BC%8Ca%3D2%EF%BC%9Bb%3D-4%EF%BC%8C%E7%9F%A5%E4%B8%8D%E9%81%93%E5%AF%B9)
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