(π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009

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(π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009
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(π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009
(π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009

(π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009
(-π)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009
=1-1/(1/2)+(2/3)^2008*(3/2)^2009
=1-2+[(2/3)^2008*(3/2)^2008]*(3/2)
=-1+[(2/3*3/2)^2008]*(3/2)
=-1+1^2008*(3/2)
=-1+3/2
=1/2
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(π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009
=1-2+(2/3)^2008×(-3/2)^2009
=-1+(2/3)^2008×(-3/2)^2008×(-3/2)
=-1+((2/3)×(3/2))^2008×(-3/2)
=-1+(-3/2)=-2.5

|-2|+(-1)-(π-√3)0次方 |-2|+(π-3)^0-(1/3)^0+(-1)^2010 (π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009 (π-)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009 两道计算题1、5^-2-(-4)^-2+(π-1)^0 2、(-1/3)^0+(-1/3)^-1+(-1/3)^-2 计算 (3.14-π)^0-(2分之1)^-2+|-3| sin(2π/3+λ)=1/2,0 sin0=0 sin(1/6π)=1/2sin(1/3π)=√3/2sin(1/2π)=1sin(2/3π)=√3/2sin(5/6π)=1/2sin(π)=0sin(-π)=0sin(-5/6π)=-1/2sin(-2/3π)=-√3/2sin(-1/2π)=-1sin(-1/3π)=-√3/2sin(-1/6π)=-1/2sin(7/6π)=-1/2sin(4/3π)=-√3/2sin(5/3π)=-√3/2sin(11/6π)=-1/ -2²-1/根号2+|(-2)²-1|+(π-3)^0+根号2/2 -2²-1/根号2+|(-2)²-1|+(π-3)^0+根号2/2 y=2cos(2x+π/3)+1,x∈【0,π／2】的值域 -1^4+(2008-π)^0+(3)^-1+(1/3)^-2-(-2^3) (2/3)^-1+(π-3)^0+(-2)^-2+丨(-2)^3丨RT sin(a+π/2)=1/3,a属于（-π/2,0),则tan a= y=sin(-1/2x+π/3)的单调递增区间（1）x属于0~π的（2）x属于-2π~2π的 (0.027)^1/3-(61/4)1/2+(2倍根号2)^﹣2/3-3^﹣1+π^0 (π-1)^0+(-1/2)^-1+|5-根号27|-2根号3 计算 (π-1)^0+(1/2)^-1+5-根号27的绝对值-2根号3 计算题