已知正方体ABCD-A'B'C'D',求证(1)AC'⊥B'C (2)AC'⊥平面CB'D'

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已知正方体ABCD-A'B'C'D',求证(1)AC'⊥B'C (2)AC'⊥平面CB'D'
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已知正方体ABCD-A'B'C'D',求证(1)AC'⊥B'C (2)AC'⊥平面CB'D'
已知正方体ABCD-A'B'C'D',求证(1)AC'⊥B'C (2)AC'⊥平面CB'D'

已知正方体ABCD-A'B'C'D',求证(1)AC'⊥B'C (2)AC'⊥平面CB'D'
(1)AC'⊥B'C
证线垂直往往是要放在面里的,怎么放在面里,找相交线呗
连B、C',BC'⊥B'C 易证,AB⊥B'C 也易证(只要证AB垂直于面BCC'B')
(2)AC'⊥平面CB'D'
证线面垂直也是找两条相交线,一条B'C已证,D'B'证法同一,在证明中说句同理就可以了