f(√x+4)=x+8√x 求f(x^2) 解法f(√x+4)=x+8√x=(√x+4)^2-16f(x)=x^2-16(x≥4)f(x^2)=x^4-16(x≤-2或x≥2)解法2 设√x+4=t大于等于4,则√x=t-4,x=(t-4)^2f(t)=(t-4)^2+8(t-4)=t^2-16f(x)=x^2-16(x≥4)f(x^2)=x^4-16(x≤-2或x≥2)教
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 19:07:10
![f(√x+4)=x+8√x 求f(x^2) 解法f(√x+4)=x+8√x=(√x+4)^2-16f(x)=x^2-16(x≥4)f(x^2)=x^4-16(x≤-2或x≥2)解法2 设√x+4=t大于等于4,则√x=t-4,x=(t-4)^2f(t)=(t-4)^2+8(t-4)=t^2-16f(x)=x^2-16(x≥4)f(x^2)=x^4-16(x≤-2或x≥2)教](/uploads/image/z/1169894-38-4.jpg?t=f%28%E2%88%9Ax%2B4%29%3Dx%2B8%E2%88%9Ax+%E6%B1%82f%28x%5E2%29+%E8%A7%A3%E6%B3%95f%28%E2%88%9Ax%2B4%29%3Dx%2B8%E2%88%9Ax%3D%28%E2%88%9Ax%2B4%29%5E2-16f%28x%29%3Dx%5E2-16%28x%E2%89%A54%EF%BC%89f%28x%5E2%29%3Dx%5E4-16%28x%E2%89%A4-2%E6%88%96x%E2%89%A52%EF%BC%89%E8%A7%A3%E6%B3%952+%E8%AE%BE%E2%88%9Ax%2B4%3Dt%E5%A4%A7%E4%BA%8E%E7%AD%89%E4%BA%8E4%2C%E5%88%99%E2%88%9Ax%3Dt-4%2Cx%3D%EF%BC%88t-4%29%5E2f%28t%29%3D%28t-4%29%5E2%2B8%28t-4%29%3Dt%5E2-16f%28x%29%3Dx%5E2-16%28x%E2%89%A54%29f%28x%5E2%29%3Dx%5E4-16%28x%E2%89%A4-2%E6%88%96x%E2%89%A52%EF%BC%89%E6%95%99)
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