sinA+cosA=-7/13 sinAcosA=-60/169 所以sinAcosA为一元二次方程x^2+7x/13-60/169=0的两根怎么得来的?sinA+cosA=-7/13 sinAcosA=-60/169只知道用韦达定理,一元二次方程x^2+7x/13-60/169=0的两根这个一元二次方程是怎么得
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![sinA+cosA=-7/13 sinAcosA=-60/169 所以sinAcosA为一元二次方程x^2+7x/13-60/169=0的两根怎么得来的?sinA+cosA=-7/13 sinAcosA=-60/169只知道用韦达定理,一元二次方程x^2+7x/13-60/169=0的两根这个一元二次方程是怎么得](/uploads/image/z/11826157-13-7.jpg?t=sinA%2BcosA%3D-7%2F13+sinAcosA%3D-60%2F169+%E6%89%80%E4%BB%A5sinAcosA%E4%B8%BA%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bx%5E2%2B7x%2F13-60%2F169%3D0%E7%9A%84%E4%B8%A4%E6%A0%B9%E6%80%8E%E4%B9%88%E5%BE%97%E6%9D%A5%E7%9A%84%3FsinA%2BcosA%3D-7%2F13+sinAcosA%3D-60%2F169%E5%8F%AA%E7%9F%A5%E9%81%93%E7%94%A8%E9%9F%A6%E8%BE%BE%E5%AE%9A%E7%90%86%2C%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bx%5E2%2B7x%2F13-60%2F169%3D0%E7%9A%84%E4%B8%A4%E6%A0%B9%E8%BF%99%E4%B8%AA%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%E6%98%AF%E6%80%8E%E4%B9%88%E5%BE%97)
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