D.P.J.这是原文His Democratic Party of Japan ended more than fifty years of nearly continuous rule by the Liberal Democratic Party.The D.P.J.won almost two-thirds of the seats in lower house elections last Sunday.Not bad after just eleven years as

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D.P.J.这是原文His Democratic Party of Japan ended more than fifty years of nearly continuous rule by the Liberal Democratic Party.The D.P.J.won almost two-thirds of the seats in lower house elections last Sunday.Not bad after just eleven years as
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D.P.J.这是原文His Democratic Party of Japan ended more than fifty years of nearly continuous rule by the Liberal Democratic Party.The D.P.J.won almost two-thirds of the seats in lower house elections last Sunday.Not bad after just eleven years as
D.P.J.
这是原文His Democratic Party of Japan ended more than fifty years of nearly continuous rule by the Liberal Democratic Party.The D.P.J.won almost two-thirds of the seats in lower house elections last Sunday.Not bad after just eleven years as a party

D.P.J.这是原文His Democratic Party of Japan ended more than fifty years of nearly continuous rule by the Liberal Democratic Party.The D.P.J.won almost two-thirds of the seats in lower house elections last Sunday.Not bad after just eleven years as
D.P.J.=Democratic Party of Japan 日本民主党

D.P.J.这是原文His Democratic Party of Japan ended more than fifty years of nearly continuous rule by the Liberal Democratic Party.The D.P.J.won almost two-thirds of the seats in lower house elections last Sunday.Not bad after just eleven years as 二维数组的等价问题*若有以下定义和赋值语句,则与&s[i][j]等价的是().int s[2][3]={0},(*p)[3],i,j;p=s; i=j=1;A) *(*(p+i)+j)B) *(p[i]+j)C) *(p+i)+j D) (*(p+i))[j ] 这段程序输出p,q,i,j的值是多少#includevoid main(){int i=5,j=5,p,q;p=(i++)+(i++)+(i++);q=(++j)+(++j)+(++j);printf(%d,%d,%d,%d ,p,q,i,j);} #include main() { int j,a[]={1,3,5,7,9,11,13,15},*p=a+5; for(j=3; j; j--)#include main(){ int j,a[]={1,3,5,7,9,11,13,15},*p=a+5;for(j=3; j; j--){ switch(j){ case 1:case 2:printf(%d,*p++); break;case 3:printf(%d,*(--p));}}}答案是9911,是怎样 int j,a[]={1,3,5,7,9,11,13,15,#include main(){ int j,a[]={1,3,5,7,9,11,13,15},*p=a+5;for(j=3; j; j--){ switch(j){ case 1:case 2:printf(%d,*p++); break;case 3:printf(%d,*(--p));}}}答案是9911,是怎样来? 对于这个答案谁能给我个解释?对于这个程序的答案是15,22,8,8,这个答案小弟我始终不明白,#includemain(){int i=5,j=5,p,q; p=(i++)+(i++)+(i++);q=(++j)+(++j)+(++j); printf(%d,%d,%d,%d,p,q,i,j);} (1/2)b m p p p j l d f h f a f j h s d f y f d v h h s x g i g d g ,中文是什 main(){int i=5,p=(i++)+(i++)+(i++);q=(++j)+(++j)+(++j);printf(%d,%d,%d,%d,p,q,i,j);} 求matlab语句解答,D()=y1()是什么意思,下边的abs是求绝对值得吗for j=1:2*p*lfor m=1:10f=cos(t-pi*(1-p)*(j-1)/(p*l))*exp(-i*m*t);y1(m)=int(f,t,-pi/(2*p*l)+pi*(j-1)/(p*l),pi/(2*p*l)+pi*(j-1)/(p*l));D(j,m)=y1(m);endendB=sum(D);B=abs( 与P字母最搭的英文名,P在最后?例如:“D.空格J”的J 地质年代中这几个字母代表什么?Q N E K J T P C D 怎么用lingo求解多目标规划呢,max =@sum(I(i):@sum(J(j):@sum(link(I,J):x(i)*w(j)*p(i,j)/d(i,j))));@for(I(i):@sum(J(j)|w(j)#eq#1:x(i)*p(i,j))>0);@for(I(i):@sum(J(j):x(i)*p(i,j)*c(j))>0);@for(J(j):@sum(link(I,J):x(i)*p(i,j)>=0));@for(l N D Z Z D S S T Y J A P H L D M? Z D G C W C Z D N Y Z Y L D Y X L K , W X G N H H , J X Z女朋友发的短信这是什么意思,像是汉字首拼音 破解下!这是汉子首拼音! C语言 p=(i++)+(i++)+(i++); q=(++j)+(++j)+(++j);void main(){  int i=5,j=5,p,q;  p=(i++)+(i++)+(i++);  q=(++j)+(++j)+(++j);  printf(%d,%d,%d,%d,p,q,i,j);  }对P=(i++)+(i++)+(i++)应理解为三个i相加,故P值为15.然后i再 a d g .j m p 组成一个单词 model is ill lingo,高手帮帮忙!1下面的是我写的 但是怎么改都有错!model:sets: varei/1..7/:t,s; varej/1..4/:size,num,p1,p2,g,b,q; links(varei,varej):x,p,m,d;endsets!目标函数;min=@sum(links:m(i,j)*((p(i,j)-p1(j))*b(j)+g(j))*t(i) q f t j q f j d e p w q #include void swap(char *a,char *b){ char *t;t=a;a=b;b=t;}main(){ char i=3,j=5,*p=&i,*q=&j;swap(p,q);printf(%d %d ,i,j);}(1)printf(%d %d ,i,j);改为printf(%d %d “,*p,*q); 结果一样,同样是:3 5(2)定义为char,没有错误,只