17.在平面直角坐标系中,对于平面内任意一点(x,y),若规定以下两种变换:①f(x,y)=(x+2,y).如f(1,1)=(3,1);②g(x,y)=(-x,-y),如g(2,2).=(-2,-2)按照以上变换有:g(f(1,1))=g(3,1)=(-3,-1)那么等于f(g(-3
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![17.在平面直角坐标系中,对于平面内任意一点(x,y),若规定以下两种变换:①f(x,y)=(x+2,y).如f(1,1)=(3,1);②g(x,y)=(-x,-y),如g(2,2).=(-2,-2)按照以上变换有:g(f(1,1))=g(3,1)=(-3,-1)那么等于f(g(-3](/uploads/image/z/11941583-23-3.jpg?t=17.%E5%9C%A8%E5%B9%B3%E9%9D%A2%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E4%B8%AD%2C%E5%AF%B9%E4%BA%8E%E5%B9%B3%E9%9D%A2%E5%86%85%E4%BB%BB%E6%84%8F%E4%B8%80%E7%82%B9%EF%BC%88x%2Cy%EF%BC%89%2C%E8%8B%A5%E8%A7%84%E5%AE%9A%E4%BB%A5%E4%B8%8B%E4%B8%A4%E7%A7%8D%E5%8F%98%E6%8D%A2%EF%BC%9A%E2%91%A0f%28x%2Cy%29%3D%EF%BC%88x%2B2%2Cy%EF%BC%89%EF%BC%8E%E5%A6%82f%281%2C1%29%3D%283%2C1%29%EF%BC%9B%E2%91%A1g%28x%2Cy%29%3D%28-x%2C-y%29%2C%E5%A6%82g%282%2C2%29.%3D%28-2%2C-2%29%E6%8C%89%E7%85%A7%E4%BB%A5%E4%B8%8A%E5%8F%98%E6%8D%A2%E6%9C%89%EF%BC%9Ag%28f%EF%BC%881%2C1%EF%BC%89%EF%BC%89%3Dg%283%2C1%29%3D%28-3%2C-1%29%E9%82%A3%E4%B9%88%E7%AD%89%E4%BA%8Ef%EF%BC%88g%28-3)
17.在平面直角坐标系中,对于平面内任意一点(x,y),若规定以下两种变换:①f(x,y)=(x+2,y).如f(1,1)=(3,1);②g(x,y)=(-x,-y),如g(2,2).=(-2,-2)按照以上变换有:g(f(1,1))=g(3,1)=(-3,-1)那么等于f(g(-3
17.在平面直角坐标系中,对于平面内任意一点(x,y),若规定以下两种变换:①f(x,y)=(x+2,y).如f(1,1)=(3,1);②g(x,y)=(-x,-y),如g(2,2).=(-2,-2)
按照以上变换有:g(f(1,1))=g(3,1)=(-3,-1)那么等于f(g(-3,4))等于 ▲ .
17.在平面直角坐标系中,对于平面内任意一点(x,y),若规定以下两种变换:①f(x,y)=(x+2,y).如f(1,1)=(3,1);②g(x,y)=(-x,-y),如g(2,2).=(-2,-2)按照以上变换有:g(f(1,1))=g(3,1)=(-3,-1)那么等于f(g(-3
(5,-4)
(5,-4)
先变换括号里面的,g(-3,4)=(3,-4)
然后f(g(-3,4))=f(3,-4)=(5,-4)
希望我的回答对您有所帮助
f(g(3.-4))=(5,-6)
复合函数从内到外嘛,g(-3,4)=(3,-4)是不是~~f(3,-4)=(5,-4)呗
很简单啦!∵g(x,y)=(-x,-y)所以g(-3,4)=(3,-4)
又因为:f(x,y)=(x+2,y)所以f(g(-3,4))=f(3,-4)=(5,-4)
g(x,y)=(-x,-y)所以g(-3,4)=(3,-4)
又因为:f(x,y)=(x+2,y)所以f(g(-3,4))=f(3,-4)=(5,-4)