Dim j%,i%,m% m = 0 For i = 1 To 3 For j = 1 To i m = m + j Next j,i Text1 = Str(m)最后m j 是多少

Dim j%,i%,m% m = 0 For i = 1 To 3 For j = 1 To i m = m + j Next j,i Text1 = Str(m)最后m j 是多少 dim m(5,5),s(5) for i=1 to 5 s(i)=0 for j=1 to 5 m(i,j)=i+j s(i)=s(i)+m(i,j) next j next ifor each x in sprint x;next x这个题的最终答案是20 25 30 35 40所不理解是就是关于问题补充部分中for each x in vb求m+mm+mmm+...+mm...mmm(n个m)要求 n ,m值 用 inputbox输入Dim m%,n%,i%,j%,a(0 To 9999999) As IntegerPrivate Sub Form_Click()m = InputBox(请输入m值 )n = InputBox(请输入n值 )For i = n To 0 Step -1a(n) = a(n) + 10 ^ (i - 1)Next iPrin 请给下面程序中的 If I = 0 Then这一句解释一下,Const n = 10Dim data()Private Sub Form_Load()Me.AutoRedraw = TrueReDim data(n)For I = 1 To ndata(I) = 10 * IPrint data(I);NextEnd SubPrivate Sub Command1_Click()Dim I%,J%,x%Static m%Print:Pr 您给我的计算公式没有去处重复的组合呀!就是33个数字的那个.如题 原程序：Sub tt() Application.ScreenUpdating = False Dim i,j,k,l,m,n As Integer Dim Ar(33) As Integer,Arsum As Long,tempSum As Long Dim x As Long Dim FS As Ob vb计算1!+3!+*****+（2n+1）!的代码Private Sub Command1_Click()Dim n As Integer, i As Integer, j As Integern = Val(InputBox(请输入N值))m = 1: Sum = 0For i = 1 To 2 * n + 1 Step (2)For j = 1 To im = m * jNext jSum = Sum + mNext iPrint SumEn 看程序,)private sub form-click()dim a(5,5) as integer,s(5) as integerfor i=1 to 5s(i)= 0for j=1 to 5m(i,j)=i+jnext jnext ifor each x in sprint x;nextend sub java中有些句子如int i=8 ,j=8,I=0;int a=5,b=6;float f=1.0f；double d=2.5d；int m=i%j;f=i/f;I=++i+j++;标题中的int m=i%j f=i/f;又是什么意思?Syestem.out.println（I=+I）;Syestem.out.println（f=+f）;口号里面的f=是什么意 lingo报错,MODEL:sets:fac/a1..a49/:Fcus/b1..b49/;link(fac,cus):M,X;endsetsdata:F=省略M=省略X=省略enddatamin=@sum(cus(j):@sum (fac(i):X(i,j)*M(j)*z(i)))+@sum(fac(j):f(j)*z(j));@bin(z);@for(fac(j):@sum(cus(i):z(i,j)) sets:shiduan/1..5/:h,t; xinghao/1..3/:NN,m,MM,G,F,Q; link(xinghao,shiduan):n,w; endsets min=@sum(xinghao(i):(G(i)*t(1)+Q(i))*n(i,1)+(w(i,1)-m(i))*n(i,1)*F(i)*t(1))+ @sum(shiduan(j)|j #ge# 2:G(i)*n(i,j)*t(j)+(w(i,j)-m(i))*n(i,j)*F(j)*t(i)+@if(n(i,j)#g vb6溢出 使用公式计算Dim a,b,c,d,e,f,g,h,i,j,k,l,m,n As LongText1.Text = aText2.Text = bText3.Text = cText4.Text = dText5.Text = eText6.Text = fg = a + 1h = 1 / gi = b / hj = d + 1k = 1 / jl = e / km = i - ln = c / m 高亮 提示溢出f = n * 怎么理解vb中 dim m(10) for i=1 to 5 m(i)=i*i next i print m(i-1) for(j=i;j>0;j--) { k=k+m[j]; if(time[j]>t)t=time[j]; if(k int i=3.j=5.m;则执行语句m=(i++)-(--j);后m,j值是多少? k(i,j)(m)=k(i,j)(m-1)-k(m,i)(m-1)*k(m,j)(m-1)/k(m,m)(m-1) 在matlab中怎么实现啊,谢谢各位大虾!k(i,j)(m)=k(i,j)(m-1)-k(m,i)(m-1)*k(m,j)(m-1)/k(m,m)(m-1) 其中k表示矩阵,k(i,j)表示矩阵的某个元素,后面的（m）或（m-1）表 用vb 求π Private Sub Form_Click()Dim i As Long,pi As Double,k As Integer,m As Doublei = 1k = 1pi = 0m = 1While (m > 0.00001)m = 1 / (2 * i - 1)pi = pi + k * mi = i + 1k = -kWendPrint π ; 4 * piEnd SubPrivate Sub Form_Click()Dim pi,c,s As Single #includemain(){int i,j,m=1;for(i=1;i0;j--){if(i*j>3)break;m*=i*j;}}输出m 物体质量为3kg,t=0时位于r=4i m,v=i+6j m/s,如一恒力f=5j N作用在物体上,求3s后