c语言计算输入的整数中的奇数和以及偶数和,比如输入的整数为12345,那么奇数和为1+3+5=9,偶数和为2+4=6我自己已经想到了#include void main(){ int sum1=0,sum2=0,i,n;printf("Please enter an integer:");scanf("%d/n",&i
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![c语言计算输入的整数中的奇数和以及偶数和,比如输入的整数为12345,那么奇数和为1+3+5=9,偶数和为2+4=6我自己已经想到了#include void main(){ int sum1=0,sum2=0,i,n;printf(](/uploads/image/z/12105165-21-5.jpg?t=c%E8%AF%AD%E8%A8%80%E8%AE%A1%E7%AE%97%E8%BE%93%E5%85%A5%E7%9A%84%E6%95%B4%E6%95%B0%E4%B8%AD%E7%9A%84%E5%A5%87%E6%95%B0%E5%92%8C%E4%BB%A5%E5%8F%8A%E5%81%B6%E6%95%B0%E5%92%8C%2C%E6%AF%94%E5%A6%82%E8%BE%93%E5%85%A5%E7%9A%84%E6%95%B4%E6%95%B0%E4%B8%BA12345%2C%E9%82%A3%E4%B9%88%E5%A5%87%E6%95%B0%E5%92%8C%E4%B8%BA1%2B3%2B5%3D9%2C%E5%81%B6%E6%95%B0%E5%92%8C%E4%B8%BA2%2B4%3D6%E6%88%91%E8%87%AA%E5%B7%B1%E5%B7%B2%E7%BB%8F%E6%83%B3%E5%88%B0%E4%BA%86%23include+void+main%28%29%7B+int+sum1%3D0%2Csum2%3D0%2Ci%2Cn%3Bprintf%28%22Please+enter+an+integer%3A%22%29%3Bscanf%28%22%25d%2Fn%22%2C%26i)
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