One litter of air at atmospheric pressure and 25C is held in a flask.the pressure of oxygen in the flask is 0.201 atm(20.4kpa).the concentration of oxygen in the flask ,in mole per litter is A 8.2 B 0.12 C0.098 D0.0082 请问选哪个 然后为什么
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![One litter of air at atmospheric pressure and 25C is held in a flask.the pressure of oxygen in the flask is 0.201 atm(20.4kpa).the concentration of oxygen in the flask ,in mole per litter is A 8.2 B 0.12 C0.098 D0.0082 请问选哪个 然后为什么](/uploads/image/z/1222026-42-6.jpg?t=One+litter+of+air+at+atmospheric+pressure+and+25C+is+held+in+a+flask.the+pressure+of+oxygen+in+the+flask+is+0.201+atm%2820.4kpa%29.the+concentration+of+oxygen+in+the+flask+%2Cin+mole+per+litter+is+A+8.2+B+0.12+C0.098+D0.0082+%E8%AF%B7%E9%97%AE%E9%80%89%E5%93%AA%E4%B8%AA+%E7%84%B6%E5%90%8E%E4%B8%BA%E4%BB%80%E4%B9%88)
One litter of air at atmospheric pressure and 25C is held in a flask.the pressure of oxygen in the flask is 0.201 atm(20.4kpa).the concentration of oxygen in the flask ,in mole per litter is A 8.2 B 0.12 C0.098 D0.0082 请问选哪个 然后为什么
One litter of air at atmospheric pressure and 25C is held in a flask.the pressure of oxygen in the flask is 0.201 atm(20.4kpa).the concentration of oxygen in the flask ,in mole per litter is
A 8.2 B 0.12 C0.098 D0.0082 请问选哪个 然后为什么
One litter of air at atmospheric pressure and 25C is held in a flask.the pressure of oxygen in the flask is 0.201 atm(20.4kpa).the concentration of oxygen in the flask ,in mole per litter is A 8.2 B 0.12 C0.098 D0.0082 请问选哪个 然后为什么
原文意思:25℃,一个大气压下,在烧瓶中盛有1L空气,氧气分压为0.201个大气压(20.4KPa),问烧瓶中氧气的浓度为多少(用mol/L)?(应该是liter,而不是litter)
计算:根据PV=nRT
标况(101KPa,273K)下,1mol气体体积为22.4L,有101*22.4=1*R*273.(1)
现在(20.4KPa,298K,1L),有20.4*1=nR*298.(2)
(2)/(1)得,n=273*20.4/(298*101*22.4)=0.008
所以选D
克拉佩龙pV=nRT 从而n/V=p/(RT),带入具体数据:pp=0.201 r=0.082 T=298.15 (单位略)。选D.