int a=1,b=3,t:若要将a和b变量中的说句进行交换,

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int a=1,b=3,t:若要将a和b变量中的说句进行交换,
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int a=1,b=3,t:若要将a和b变量中的说句进行交换,
int a=1,b=3,t:若要将a和b变量中的说句进行交换,

int a=1,b=3,t:若要将a和b变量中的说句进行交换,
t=a;用t保存a的值
a=b;把b的值赋给a
b=t;把用t保存的a的值交给b
用t来做中间变量完交换

int a=1,b=3,t:若要将a和b变量中的说句进行交换, void fun(int a,int b) { int t; t=a;a=b;b=t; } main()void fun(int a,int b){ int t; t=a;a=b;b=t; } main() { int c[10]={1,2,3,4,5,6,7,8,9,0}.i; for(i=0;i #include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i #include void fun(int a,int b) {int t; t=a;a=b;b=t; } main() {int c[6]={1,2,3,4,5,6},i;for(i=0;i #include stdio.h void fun(int a,int b) { int t; t=a,a=b,b=t; } main() { int c[10]={1,2,3,4,5,6,7#include stdio.hvoid fun(int a,int b){int t;t=a,a=b,b=t;}main(){int c[10]={1,2,3,4,5,6,7,8,9,0},i;for(i=0;i C++ 关于求两个数的最大公约数和最小公倍数我设计的程序是#includeusing namespace std;void main(){int a=0;int b=0;int r,p;coutb;if (a>b){ t=a;b=a;b=t;}else{ a=a;b=b;}for(int r=1,int p=1;i c语言这段程序看不懂int fun(int a,int b,int c){ int t; t=(a>b)?(b>c?b:(a>c?c:a)):((a>c)?a:((b>c)?c:b)); return t; } #include void main( ) { int a=3,b=5; int *p,*q; void f1(int x,int y);void f2(int *x,int *y);p=&a; q=&b;f1(*p,*q) ;printf(a=%d ,b=%d ,a,b);f2(p,q);printf(a=%d ,b=%d ,a,b);}void f1(int x,int y) { int t;t=x; x=y; y=t;}void f2(int *x,int *y) { int int a=1,b=2,c=3,t;while (a swap交换函数,用指针实现.#include stdafx.hvoid swap(int &a,int &b ){int* p=&a;int* q=&b; int* t ;if(*p>*q){ t=p;p=q;q=t;}//a=*p;//b=*q;}int main(){int a=12;int b= 1;printf(a=%d b = %d ,a,b);swap(a,b);printf(a=%d b = %d ,a,b);re #include int a=3,b=5; max (int a,int b) {int c; c=a>b?a:b; return (c); } void main() {int int a=5,b=1,t; t=(a vfp实验题目中,t=alltrim(str(a/b,int(a/b)+3, #includeusing namespace std;template int Search(T a[],int now,int all){int min,j = now;min = a[now];for(int i = now + 1; i < all; i ++){if(min > a[i]){min = a[i];j = i;}}return j;}template void swap(int& a,int& b){T p;p = a;a = b;b = p;}template void void swap1(int c0[],int c1[]) { int t; t=c0[0];c0[0]=c1[0];c1[0]=t; } void swap2(int *c0,int *c1) {void swap1(int c0[],int c1[]){ int t;t=c0[0];c0[0]=c1[0];c1[0]=t;}void swap2(int *c0,int *c1){int t;t=*c0;*c0=*c1;*c1=t;}void main(){int a[2]={3,5},b[ int a,b; b = a >> 执行下面语句后,a 和 b 的值分别为( )int a=5 ,b=3 ,t ; int &ra=a ; int &rb=b ; t=ra ; ra=rb ; rb=t ;a.5和3 b.3和3 c.3和5 d.5和5 #include int b=2; int fun(int *k) {b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8},