C语言 三角函数 b=atan(Y/X)+(acos((X*X+Y*Y-2*L*L)/2*L*L))/2;结果b是弧度还是度数?还有acos((X*X+Y*Y-2*L*L)/2*L*L)中的(X*X+Y*Y-2*L*L)/2*L*L有范围限制吗
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![C语言 三角函数 b=atan(Y/X)+(acos((X*X+Y*Y-2*L*L)/2*L*L))/2;结果b是弧度还是度数?还有acos((X*X+Y*Y-2*L*L)/2*L*L)中的(X*X+Y*Y-2*L*L)/2*L*L有范围限制吗](/uploads/image/z/12378080-56-0.jpg?t=C%E8%AF%AD%E8%A8%80+%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0+b%3Datan%28Y%2FX%29%2B%28acos%28%28X%2AX%2BY%2AY-2%2AL%2AL%29%2F2%2AL%2AL%29%29%2F2%3B%E7%BB%93%E6%9E%9Cb%E6%98%AF%E5%BC%A7%E5%BA%A6%E8%BF%98%E6%98%AF%E5%BA%A6%E6%95%B0%3F%E8%BF%98%E6%9C%89acos%28%28X%2AX%2BY%2AY-2%2AL%2AL%29%2F2%2AL%2AL%29%E4%B8%AD%E7%9A%84%28X%2AX%2BY%2AY-2%2AL%2AL%29%2F2%2AL%2AL%E6%9C%89%E8%8C%83%E5%9B%B4%E9%99%90%E5%88%B6%E5%90%97)
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C语言 三角函数 b=atan(Y/X)+(acos((X*X+Y*Y-2*L*L)/2*L*L))/2;结果b是弧度还是度数?还有acos((X*X+Y*Y-2*L*L)/2*L*L)中的(X*X+Y*Y-2*L*L)/2*L*L有范围限制吗
C语言 三角函数
b=atan(Y/X)+(acos((X*X+Y*Y-2*L*L)/2*L*L))/2;
结果b是弧度还是度数?
还有acos((X*X+Y*Y-2*L*L)/2*L*L)中的(X*X+Y*Y-2*L*L)/2*L*L有范围限制吗
C语言 三角函数 b=atan(Y/X)+(acos((X*X+Y*Y-2*L*L)/2*L*L))/2;结果b是弧度还是度数?还有acos((X*X+Y*Y-2*L*L)/2*L*L)中的(X*X+Y*Y-2*L*L)/2*L*L有范围限制吗
对于matlab,三角函数默认是以弧度为单位,如果在实数范围内讨论,反余弦函数的定义域当然有范围限制,一旦超出[-1, 1]的范围,就只能得到虚数值.
C语言 三角函数 b=atan(Y/X)+(acos((X*X+Y*Y-2*L*L)/2*L*L))/2;结果b是弧度还是度数?还有acos((X*X+Y*Y-2*L*L)/2*L*L)中的(X*X+Y*Y-2*L*L)/2*L*L有范围限制吗
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