设z≠0,x、y、z满足4x-7y-5z=0、2x-y-z=0,求x:y

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设z≠0,x、y、z满足4x-7y-5z=0、2x-y-z=0,求x:y
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设z≠0,x、y、z满足4x-7y-5z=0、2x-y-z=0,求x:y
设z≠0,x、y、z满足4x-7y-5z=0、2x-y-z=0,求x:y

设z≠0,x、y、z满足4x-7y-5z=0、2x-y-z=0,求x:y
1,2两式都移项得:4x-7y=5z……3式,2x-y=z……4式 3式-4式*2得:y=-0.6z 3式-4式*7得:x=0.2z 所以x:y=1:(-3)