一道奥数因式分解题(6x-1)(2x-1)(3x-1)(x-1)+x²要看得懂

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 20:07:01
一道奥数因式分解题(6x-1)(2x-1)(3x-1)(x-1)+x²要看得懂
xTJA~^I8n oy \FgmH5)Ujʞ͕33ѨP7ߙz%gvFZl1ahf)&9ŏ>- 6e!3LƟeYf*y? 1+142-Fs&> jdt^Y#~V{~G؄qL9px ro߼O~sފReR",#%Bҩ6`;NHi8ɦ-N&8ho lC6` Y FtiBbJGJdrIФༀqMy)i>F?zWRAL%46sJҔ3ZǃZ8೸o;7ٗ,HG8U=Mj! Lqsk~r\0_C؍g@MUZ f(0jhDw'2

一道奥数因式分解题(6x-1)(2x-1)(3x-1)(x-1)+x²要看得懂
一道奥数因式分解题
(6x-1)(2x-1)(3x-1)(x-1)+x²
要看得懂

一道奥数因式分解题(6x-1)(2x-1)(3x-1)(x-1)+x²要看得懂
利用分组法,
2x-1)(3x-1)(6x-1)((x-1)+x²
(6X^2-7X+1)(6X2-5X+1)+X^2
设6X^2-5X+1=a
原式=(a+2x)a+x²=a^2+2ax+x^2(这就跟初二时课本上的
a^2+2ab+b^2=(a+b)^2一样)=(a+x)^2
将a带入,得到=(6x^2-6x+1)^2
有数学难题加我好友呀啊

(6x-1)(2x-1)(3x-1)(x-1)+x²
=[(6x-1)(x-1)][(2x-1)(3x-1)]+x^2
=(6x^2-7x+1)(6x^2-5x+1)+x^2
=[(6x^2-6x+1)-x][(6x^2-6x+1)+x]+x^2
=(6x^2-6x+1)^2-x^2+x^2
=(6x^2-6x+1)^2


(6x-1)(2x-1)(3x-1)(x-1)+x²
=(6x²-5x+1)(6x²-7x+1)+x²
=(6x²-5x+1)²-2x(6x²-5x+1)+x²
=(6x²-5x+1-x)²
=(6x²-6x+1)²

(6x-1)×(x-1)×(2x-1)×(3x-1)+x²
=(6x²-7x+1)(6x²-5x+1)+x²
=(6x²-5x+1)²-2x(6x²-5x+1)+x²
=(6x²-5x+1-x)²
=(6x²-6x+1)²

第一个和第四个乘,第二个和第三个
(6X2-7X+1)(6X2-5X+1)+X2
设A=6X2-6X+1
则原式=(A-X)(A+X)+X2
=A2-X2+X2
=A2
=(6X2-6X+1)2