等差数列中
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 21:43:42
![等差数列中](/uploads/image/z/12414209-41-9.jpg?t=%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%E4%B8%AD)
xQn@QDQy14w<AH $*RRReQ_`4@P5sΜNOv|맃6lKg+eln u[fYTڂl[Eh^v]p?
3 {?н_c8kIDW
[Bx3B)mwB&Bg*TqBB
Z+z%/?^g
3 r
!&9fBJm
KI}4cq@+ z%2Y.~>~'Ki}1yS(Dz$Չ2AYEr\A,cE-ūC{p:?Vds
p!h[%Y&п^Zd:^~,D_ %L%#P:=]
@@6&T3t2wPI Bg.rZuxU,9J1qe
等差数列中
等差数列中
等差数列中
h分共和国放假擐甲挥戈
a1=5/6
a(n+1)= (1/3)an + (1/2)^(n+1)
a(n+1) -3(1/2)^(n+1) = (1/3)[an -3(1/2)^n]
{an -3(1/2)^n}是等比数列,q=1/3
an -3(1/2)^n = (1/3)^(n-1).(a1 -3(1/2))
= -2(1/3)...
全部展开
a1=5/6
a(n+1)= (1/3)an + (1/2)^(n+1)
a(n+1) -3(1/2)^(n+1) = (1/3)[an -3(1/2)^n]
{an -3(1/2)^n}是等比数列,q=1/3
an -3(1/2)^n = (1/3)^(n-1).(a1 -3(1/2))
= -2(1/3)^n
an =3(1/2)^n -2(1/3)^n
bn= 2^n.an
= 3 - 2(2/3)^n
Sn =b1+b2+...+bn
= 3n - 2[ (2/3)[ 1- (2/3)^n] / (1-2/3) ]
= 3n - 4[ 1- (2/3)^n ]
收起