设总体X~N(0.1) X1,X2,.Xn 为简单随机样本,试问该统计量是服从什么分布:{ [ (n/3)-1]* ∑''3,i=1'' Xi² } / ( ∑''n,i=4'' Xi² ) 答案是服从自由度为(3,n-3 )的F 分布,不用太详细,但是也不能太简陋.
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![设总体X~N(0.1) X1,X2,.Xn 为简单随机样本,试问该统计量是服从什么分布:{ [ (n/3)-1]* ∑''3,i=1'' Xi² } / ( ∑''n,i=4'' Xi² ) 答案是服从自由度为(3,n-3 )的F 分布,不用太详细,但是也不能太简陋.](/uploads/image/z/12463493-5-3.jpg?t=%E8%AE%BE%E6%80%BB%E4%BD%93X%7EN%280.1%29+X1%2CX2%2C.Xn+%E4%B8%BA%E7%AE%80%E5%8D%95%E9%9A%8F%E6%9C%BA%E6%A0%B7%E6%9C%AC%2C%E8%AF%95%E9%97%AE%E8%AF%A5%E7%BB%9F%E8%AE%A1%E9%87%8F%E6%98%AF%E6%9C%8D%E4%BB%8E%E4%BB%80%E4%B9%88%E5%88%86%E5%B8%83%EF%BC%9A%7B+%5B+%28n%2F3%29-1%5D%2A+%E2%88%91%27%273%2Ci%3D1%27%27+Xi%26%23178%3B+%7D+%2F+%28+%E2%88%91%27%27n%2Ci%3D4%27%27+Xi%26%23178%3B+%29+%E7%AD%94%E6%A1%88%E6%98%AF%E6%9C%8D%E4%BB%8E%E8%87%AA%E7%94%B1%E5%BA%A6%E4%B8%BA%EF%BC%883%2Cn-3+%EF%BC%89%E7%9A%84F+%E5%88%86%E5%B8%83%2C%E4%B8%8D%E7%94%A8%E5%A4%AA%E8%AF%A6%E7%BB%86%2C%E4%BD%86%E6%98%AF%E4%B9%9F%E4%B8%8D%E8%83%BD%E5%A4%AA%E7%AE%80%E9%99%8B.)
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