中心在原点,一个焦点为(0,4)且过点(3,0)的椭圆的方程怎样求?不明白a²-b²=c²? 能再回答一下吗,因为我比较笨的,谢谢
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![中心在原点,一个焦点为(0,4)且过点(3,0)的椭圆的方程怎样求?不明白a²-b²=c²? 能再回答一下吗,因为我比较笨的,谢谢](/uploads/image/z/12487559-23-9.jpg?t=%E4%B8%AD%E5%BF%83%E5%9C%A8%E5%8E%9F%E7%82%B9%2C%E4%B8%80%E4%B8%AA%E7%84%A6%E7%82%B9%E4%B8%BA%EF%BC%880%2C4%EF%BC%89%E4%B8%94%E8%BF%87%E7%82%B9%EF%BC%883%2C0%EF%BC%89%E7%9A%84%E6%A4%AD%E5%9C%86%E7%9A%84%E6%96%B9%E7%A8%8B%E6%80%8E%E6%A0%B7%E6%B1%82%3F%E4%B8%8D%E6%98%8E%E7%99%BDa%26sup2%3B-b%26sup2%3B%3Dc%26sup2%3B%EF%BC%9F+%E8%83%BD%E5%86%8D%E5%9B%9E%E7%AD%94%E4%B8%80%E4%B8%8B%E5%90%97%EF%BC%8C%E5%9B%A0%E4%B8%BA%E6%88%91%E6%AF%94%E8%BE%83%E7%AC%A8%E7%9A%84%EF%BC%8C%E8%B0%A2%E8%B0%A2)
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