(x-3)÷2=7、5,求x
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(x-3)÷2=7、5,求x
(x-3)÷2=7、5,求x
(x-3)÷2=7、5,求x
用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+.
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(x-3)÷2=7、5,求x
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x^2-2x-1=0求:x^4+x^3-5x^2-7x+5的值
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