已知动直线y=kx交圆(x-2)^2+y^2=4于坐标原点O和点A,交直线x=4于点B,若动点M满足向量OM=向量AB,动点M的轨迹C的方程为F(x,y)=0(1)试用k表示点A,点B的坐标(2)求动点M的轨迹方程F(x,y)=0
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![已知动直线y=kx交圆(x-2)^2+y^2=4于坐标原点O和点A,交直线x=4于点B,若动点M满足向量OM=向量AB,动点M的轨迹C的方程为F(x,y)=0(1)试用k表示点A,点B的坐标(2)求动点M的轨迹方程F(x,y)=0](/uploads/image/z/12513765-21-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%8A%A8%E7%9B%B4%E7%BA%BFy%3Dkx%E4%BA%A4%E5%9C%86%28x-2%29%5E2%2By%5E2%3D4%E4%BA%8E%E5%9D%90%E6%A0%87%E5%8E%9F%E7%82%B9O%E5%92%8C%E7%82%B9A%2C%E4%BA%A4%E7%9B%B4%E7%BA%BFx%3D4%E4%BA%8E%E7%82%B9B%2C%E8%8B%A5%E5%8A%A8%E7%82%B9M%E6%BB%A1%E8%B6%B3%E5%90%91%E9%87%8FOM%3D%E5%90%91%E9%87%8FAB%2C%E5%8A%A8%E7%82%B9M%E7%9A%84%E8%BD%A8%E8%BF%B9C%E7%9A%84%E6%96%B9%E7%A8%8B%E4%B8%BAF%28x%2Cy%29%3D0%EF%BC%881%EF%BC%89%E8%AF%95%E7%94%A8k%E8%A1%A8%E7%A4%BA%E7%82%B9A%2C%E7%82%B9B%E7%9A%84%E5%9D%90%E6%A0%87%EF%BC%882%EF%BC%89%E6%B1%82%E5%8A%A8%E7%82%B9M%E7%9A%84%E8%BD%A8%E8%BF%B9%E6%96%B9%E7%A8%8BF%28x%2Cy%29%3D0)
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